The sum of interior angle ( Sum-of-interior-angles-n-gon) of n-gon is: If we have a , Then

the sum of the interior angles of a convex 45-gon is 7740.

Sum= 2340 Degrees A+

Sum of what aspect of a 20-gon: the length of its sides, its interior angles, its exterior angles, its apothems?

Sum of exterior angles: 360 degrees Sum of interior angles: 2160

It is: 180*11 = a sum of 1980 degrees

If you mean the sum of its interior angles then it is 4140 degrees

The sum of the interior angles of a n-gon is (n-2)*180 degrees (n>2). So the sum for a 50-gon would be 48*180 = 8640 degrees.

Sum of the angles of a regular polygon = (#sides - 2) * 180. Sum of 20-gon angles = (20-2) * 180 = 3240

hahaa.... i don't know!

The sum of the interior angles of a n-gon is (n-2)*180 degrees. Convexity does not matter. So for a 17-gon, the sum would be 15*180 = 2700 degrees.

the sum of the interior angles of a 35-gon.

The sum of the exterior angles of any polygon is 360o.

The sum of the exterior angles of ANY polygon is 360 degrees.

The sum is 95*180 = 17,100 degrees

The sum is: (11-2)*180 = 1620 degrees

180x28 is the sum of the interior angles in a 30- gon

The sum of the interior angles of an n-gon is found by the formula: (n-2)*(180) degrees. So a 38-gon would have (38-2)*(180) degree sum for its interior angles, which equals 6,480 degrees.

The exterior sum of angles of any polygon is always 360 degrees.

(number of sides-2)*180 = sum of interior degrees

The question makes no sense since a 18-gon cannot be added. You can add the measures of its interior or exterior angles, or the lengths of its sides, its diagonals and so on. But there is no such thing as a "sum of 18-gon".

Sum of exterior angles = 360 deg Sum of interior angles = (29-2)*180 = 4860 degrees.

360 degrees. (All polygons have an exterior angle sum of 360 degrees.)

The sum of the exterior angles of a polygon, with any number of sides, is 360 degrees.

The sum of the exterior angle of ANY polygon is 360 degrees.

The sum of the exterior angles of a polygon with ANY number of sides, is 360 degrees.

The sum of the exterior angles of a polgon - no matter how many sides - is 360 degrees.

Measure each side and add them up to get the sum of the side-lengths = perimeter.

The sum of the interior angles add up to 3240 degrees.

The interior angles of a 30-gon add up to 5040 degrees

Assuming you mean a regular 16-gon (also known as a hexadecagon), the sum of the interior angles is 2520 degrees, or 14 Pi radians.

The sum of the measures of the n interior angles of an n-gon is 180(n-2) 180 (45-2) = 180 * 43 = 7740 degrees

The sum of the interior angles is (9-2)*180 = 7*180 = 1260 degrees.

The sum of the exterior angles of a polygon, no matter how many sides, is 360 degrees.

The formula is: (20-2)*180 = 3240 degrees which is the total sum of interior angles

Sum of interior angles of a n-gon is 180*(n-2) So for a 10-gon (decagon), the sum would be 180*8 = 1440 degrees. That is true whether the polygon is convex or not (as long as its sides do not intersect).

180⁰(38 - 2) = 6,480⁰

It is: 998*180 = 179640 degrees

360o; the sum of the exterior angles of any polygon is 360, as given in the formula E = 360.

The sum of the exterior angles of every polygon is 360 degrees.

Sum of interior angles =(no. of sides - 2)180 =(55-2)180 =9540 degrees

Total sum of interior angles: (37-2)*180 = 6,300 degrees

15-gon??? assuming you mean a pendedecagon, here is your answer: 2,340 degrees

The interior angles of an 11-gon add up to 1620 degrees

The sum of the exterior angles of any convex polygon is always 360 degrees. The sum of the interior angles of any convex n-gon is (n-2) * 180 degrees, because any convex n-gon can be represented as n-2 triangles, and the sum of the interior angles of a triangle is 180 degrees.

The sum of the exterior angles is always 360 degrees. The sum of the interior angles is (14-2)(180 degrees) or 12x180 which is 2160 degrees.

3240. Stick it to Iqity.

it equals to 3420 degrees

its 2880 degrees total

They add up to 5400 degrees