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What is the sum of all possible four digit numbers using the digits 4068?
Wiki User
∙ 12y ago
-- If you accept 4-digit numbers with 'zero' as the first digit, then
there are 24 possibilities, and their sum is 119,988 .
-- If the first digit can't be a 'zero', then there are 18 possibilities,
and their sum is 115,992 .
Note: I didn't repeat any digits.
-- If you allow repeated digits, and accept leading zeros, then there are 256 possibilities,
and their sum is 1,279,872.
-- If you allow repeated digits but not leading zeros, then there are only 192 possibilities,
and their sum is 1,247,904.
Wiki User
∙ 12y ago
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How many possible 3 digit numbers can be made using the digits 604?
There are 4 possible numbers if the digits are not repeated; 18 if they are. Those are 3-digit numbers, assuming that zero would not be a leading digit. If zero is allowed for a leading digit, then you can have 6 for the non repeated, and 27 if repetition.
What are the the 3 digit numbers using 1345678?
Using the digits of 1345678, there are 210 three digit numbers in which no digit is repeated.
How many 13 digit numbers are possible by using the digits 12345 which are divisible by 4 if repetition of digits is not allowed?
If repetition of digits isn't allowed, then no13-digit sequencescan be formed from only 5 digits.
How many 3-digit numbers using the digits 0-7 are possible if repetition are allowed?
290
How many different 3-digit numbers less than 500 can be made using the digits 345 and 6 if the digits can be only used only once?
There are 2 possible digits for the first digit (3 or 4), leaving 3 possible digits for the second digit (5 and 6 and whichever was not chosen for the first), leaving 2 possible digits for the third. Thus there are 2 × 3 × 2 = 12 possible 3 digit numbers.
How many different three digit numbers can you form using the digits 2 5 and 7?
6 possible 3 digit combonations
How many 2-digit numbers can be formed using the digits 1 3 7 if repetition of digits is allowed?
Possible solutions - using your rules are:- 11,13,17,31,33,37,71,73 &77
How many different three digit numbers can you form using the digits 1 2 3 5 6 7 and 9 without repetition?
There are seven possible digits for the first digit and 6 digits for the second (minus one digit for the digit used as the first digit) and 5 options for the last digit (minus one again for the second digit) and then you just multiply them all together to get a total possible combination of 210 numbers that are possible.
How many possible 5 digit combinations are there using 5 digits?
Possible 5 digit combinations using 5 digits only 1 time is 5! or 5*4*3*2*1 or 120. Using 5 digits where numbers can be used 5 times is 55 or 3125.
How many two digit numbers can be formed from the digits 7341 if none of the digit can be repeated?
There are twelve possible solutions using the rule you stated... 13,14,17,31,34,37,41,43,47,71,73 & 74
How many four digits numbers can be formed using 0123456789?
Assuming that the first digit of the 4 digit number cannot be 0, then there are 9 possible digits for the first of the four. Also assuming that each digit does not need to be unique, then the next three digits of the four can have 10 possible for each. That results in 9x10x10x10 = 9000 possible 4 digit numbers. If, however, you can not use the same number twice in completing the 4 digit number, and the first digit cannot be 0, then the result is 9x9x8x7 = 4536 possible 4 digit numbers. If the 4 digit number can start with 0, then there are 10,000 possible 4 digit numbers. If the 4 digit number can start with 0, and you cannot use any number twice, then the result is 10x9x8x7 = 5040 possilbe 4 digit numbers.
How many 6 digit numbers can be formed using the digits 123456789?
There are 60480 numbers.
