Each interior angle measures 60 degrees and they add up to 180 degrees
It is in fact an equilateral triangle
360 degrees and the polygon is an equilateral triangle.
1440 degrees
1440 degrees
5
If it's a regular polygon then each exterior angle measures 36 degrees
What is the sum of the measures of the exterior angles of a regular polygon with ten sides
Hint: in a regular polygon interior plus exterior = 180o, always.
360 degrees and the polygon is an equilateral triangle.
How many sides does a regular polygon have if each exterior angle measures 20?
The sum of a regular polygon's interior angles is always equal to (n-2) * 180, where n is the number of sides in the polygon. Given that one exterior angle measures 40 degrees, we can find the interior angle by subtracting 40 from 180 degrees (since the exterior and interior angles are supplementary) to get 140 degrees. So, the sum of the interior angles of the regular polygon is 140 * n.
The sum of the exterior angles of a regular polygon = 360° If an exterior angle measures 8° then the number of sides = 360/8 = 45
1440 degrees
1440 degrees
36
8
18
12