1/2 (equal to 0.5, or 50%).
Experimental probability is calculated by taking the data produced from a performed experiment and calculating probability from that data. An example would be flipping a coin. The theoretical probability of landing on heads is 50%, .5 or 1/2, as is the theoretical probability of landing on tails. If during an experiment, however, a coin is flipped 100 times and lands on heads 60 times and tails 40 times, the experimental probability for this experiment for landing on heads is 60%, .6 or 6/10. The experimental probability of landing on tails would be 40%, .4, or 6/10.
No heads means that every toss lands tails. (0.5)30= 9.3 x 10-10 Note that 109 = 1 trillion, so the probability can be stated this event is likely to occur about 9 times in 10 trillion tosses.
1/2, or 50% since you are only asking what the probability of the last outcome is.
If p is the probability that any one toss lands on "heads", the probability that exactly 4 toss out of 8 lands on head is this: p^4 * (1-p)^4 * C(4,8) Where C(k,n) is an old notation for n! / ( k! * (n-k)! ) So C(4,8) = 8! / ( 4! * 4!) = 8*7*6*5 / 24 = 70 If your coin is well balanced, p is 50% and you get your answer: (0.5)^8 * 70 = 70/256 =~ 27,34%
50%
lands heads up
The probability of the coin flip being heads or tails is 100%.
Experimental probability is calculated by taking the data produced from a performed experiment and calculating probability from that data. An example would be flipping a coin. The theoretical probability of landing on heads is 50%, .5 or 1/2, as is the theoretical probability of landing on tails. If during an experiment, however, a coin is flipped 100 times and lands on heads 60 times and tails 40 times, the experimental probability for this experiment for landing on heads is 60%, .6 or 6/10. The experimental probability of landing on tails would be 40%, .4, or 6/10.
No heads means that every toss lands tails. (0.5)30= 9.3 x 10-10 Note that 109 = 1 trillion, so the probability can be stated this event is likely to occur about 9 times in 10 trillion tosses.
Geometric Probability
If it is a fair coin, the probability is 1/2.
1/2, or 50% since you are only asking what the probability of the last outcome is.
Since it is a fair coin, the probability is 0.5
One in six. One in two.
1/6
If p is the probability that any one toss lands on "heads", the probability that exactly 4 toss out of 8 lands on head is this: p^4 * (1-p)^4 * C(4,8) Where C(k,n) is an old notation for n! / ( k! * (n-k)! ) So C(4,8) = 8! / ( 4! * 4!) = 8*7*6*5 / 24 = 70 If your coin is well balanced, p is 50% and you get your answer: (0.5)^8 * 70 = 70/256 =~ 27,34%
50%