Typical notebook paper size is 8.5 inches in width and 11 inches in length.
The size and thickness varies. I generally use spiral-bound reporters' note books (23 mm x 12.5 mm) with 160 pages, and is 6 mm thick, approximately.
The typical notebook is around 10in.
[width] x [length] x 6 = Area of a cube . Note: width and length should be the same if its a cube.
That depends both on the size (length, width) of the paper, and on its thickness. The paper I use for printing has 75 grams per square meter; you can base your calculations on that (convert length and width to meters, and multiply by 75 to get grams per sheet). Or use some other thickness, depending on the paper you use.Please note that a gram is not technically a unit of weight, but a unit of mass.
Generally it is 8x12 inches.
Width = Area/Length = 9375/75 = 125 feet. PS (A pedantic note): The longer dimension is usually called the length.
You can contro the image's length and width in HTML by using the following code:Note: The ? indicates the number you coose. The "?" indicates the location of the image you wish to select.
A standard sheet of paper is 8 1/2 x 11 so a standard notebook would be very close to those dimensions.
The length works out as 12 cm and the width works out as 5 cm Check: 2*(12+5) = 34 cm which is the perimeter
Take its length and multiply by its width. For example:- Length-30cm,Width-19cm Area=length x width =30x19(cm) =570 units2. Answer=The area of the rectangle is 570 units2. Note: Make sure to use the same units for length and width. The result is measured in units².
loan
If this is for a square or rectangle... the formula is: Area=Length x Width so, if you know the Area and the Length, the Width would be found this way: Area/Length = Width, or written out: Area divided by Length = Width Example: A rectangle where the known dimensions are: Area = 30 feet squared Length = 6 feet 30 feet squared / 6 feet = 5 feet Answer: Width = 5 feet Special Note: The units for the Area, meaning feet or inches or centimeters or whatever unit you're measuring in, the "Area" answer is always in Square Units. This is because as you multiply the length units times the width units, the units are multiplied and are thus "squared units." Hope this helps!
Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.
Bond -yee i did it myself lol-