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Typical notebook paper size is 8.5 inches in width and 11 inches in length.

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4w ago
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6y ago

The size and thickness varies. I generally use spiral-bound reporters' note books (23 mm x 12.5 mm) with 160 pages, and is 6 mm thick, approximately.

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14y ago

The typical notebook is around 10in.

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Q: What is the length and width of note book paper?
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Whats the method for finding the area of a rectangle?

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If this is for a square or rectangle... the formula is: Area=Length x Width so, if you know the Area and the Length, the Width would be found this way: Area/Length = Width, or written out: Area divided by Length = Width Example: A rectangle where the known dimensions are: Area = 30 feet squared Length = 6 feet 30 feet squared / 6 feet = 5 feet Answer: Width = 5 feet Special Note: The units for the Area, meaning feet or inches or centimeters or whatever unit you're measuring in, the "Area" answer is always in Square Units. This is because as you multiply the length units times the width units, the units are multiplied and are thus "squared units." Hope this helps!


How do you calculate the top dimensions of a rectangle if you know its perimeter and bottom area?

Important to note are these formulae: Perimeter_of_rectangle = 2 x (length + width) Area_of_rectangle = length x width So if the perimeter and area are known, then: 2 x (length + width) = perimeter => length + width = perimeter / 2 => length = perimeter / 2 - width length x width = area => (perimeter / 2 - width) x width = area (substituting for length given above) => perimeter / 2 x width - width2 = area => width2 - perimeter / 2 x width + area = 0 which is a quadratic and can be solved either by factorization or by using the formula: width = (perimeter / 2 +/- sqrt(perimeter2 / 4 - 4 x area)) / 2 = (perimeter +/- sqrt(perimeter2 - 16 x area)) / 4 This will provide two values for the width. However, each of these values is the length for the other, so the larger value is the length and the smaller value is the width. Sometimes only 1 value will be found for the width above. In this case, the rectangle is actually a square which means that the length and width are both the same. Examples: 1. perimeter = 6, area = 2 width2 - perimeter / 2 x width + area = 0 => width2 - 6 / 2 x width + 2 = 0 => width2 - 3 x width + 2 = 0 => (width - 2) x (width - 1) = 0 => width = 2 or 1. So the length is 2 and the width is 1. 2. perimeter = 12, area = 9 width2 - perimeter / 2 x width + area = 0 => width2 - 12 / 2 x width + 9 = 0 => width2 - 6 x width + 9 = 0 => (width - 3)2 = 0 => width = 3 So the rectangle is a square with both length and width of 3.


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