Molecular equation: 2NaOH(aq) + SrCl2(aq) ==> 2NaCl(aq) + Sr(OH)2(s)Net ionic: Sr^2+(aq) + 2OH^-(aq) ==> Sr(OH)2(s)
Na^+ and Cl^- are spectator ions.
2H+(aq) + 2NO3-(aq) + Sr(OH)2(s) ---> Sr2+(aq) + 2NO3- (aq) + 2H2O(l)
As all possible products are aqueous, there is no reaction between aqueous magnesium nitrate and aqueous calcium chloride. Mg(NO3)2(aq) + CaCl2(aq) --> no reaction
Sr^2+(aq)+2NO3^-(aq) ---> Sr(NO3)2(s)
This is not a net ionic equation.
Sr(NO3)2
FeCl3 + NaOH
Sodium hydroxide plus hydrochloric acid equals sodium chloride plus water.
Copper chloride + Sodium hydroxide --> Copper hydroxide + sodium chloride
Iron chloride and sodium hydroxide will make iron hydroxide and sodium chloride. For Iron II chloride the equation is: 2NaOH(aq) + FeCl2(aq) --> 2NaCl(aq) + Fe(OH)2(S). For Iron III chloride the equation is: 3NaOH(aq) + FeCl3(aq) --> 3NaCl(aq) + Fe(OH)3(S).
The compound copper (III) chloride doesn't exist !
= iron hydroxide plus sodium chloride
FeCl3 + NaOH
Sodium hydroxide plus hydrochloric acid equals sodium chloride plus water.
Copper chloride + Sodium hydroxide --> Copper hydroxide + sodium chloride
Iron chloride and sodium hydroxide will make iron hydroxide and sodium chloride. For Iron II chloride the equation is: 2NaOH(aq) + FeCl2(aq) --> 2NaCl(aq) + Fe(OH)2(S). For Iron III chloride the equation is: 3NaOH(aq) + FeCl3(aq) --> 3NaCl(aq) + Fe(OH)3(S).
Sodium hydroxide is prepared from sodium chloride by the electrolysis of the solution.
Iron (II) chloride and sodium hydroxide react to produce iron (II) hydroxide and sodium chloride. FeCl2(aq) + NaOH(aq) --> Fe(OH)2(s) + NaCl(aq) This is a double replacement/displacement reaction.
The compound copper (III) chloride doesn't exist !
HCl + NaOH = NaCl + H2O
No Sodium hydroxide solution results -- not sodium chloride.
It will form sodium chloride and sulfur hydroxide
2NaOH (aq) + SrCl2 (aq) ==> NaCl (aq) + Sr(OH)2 (s)