You can calculate log to any base by using: logb(x) = ln(x) / ln(b) [ln is natural log], so if you have logb(e) = ln(e) / ln(b) = 1 / ln(b)
No. Log x may be written more explicitly as log10(x). That is, the logarithm of x to the base 10. Assuming that In x is a misprint for ln x, this is loge(x) ie the logarithm of e to the base e. log10(x) = loge(x)/loge(10)
Yes, if p=1 that means an event is 100% certain to happen. For example, p value for picking a day of the week in the Enlish Language that ends in AY is 1 or 100%.P values can be anywhere between 0 and 1 inclusive. For for an event, E, we can always say 0< or equal to P(E)< or equal to 1.
log base e = ln.
e=mc2
Speaking natural logs, it's '1'.Speaking common base-10 logs, it can be represented symbolically but not written exactly.
No. Log x may be written more explicitly as log10(x). That is, the logarithm of x to the base 10. Assuming that In x is a misprint for ln x, this is loge(x) ie the logarithm of e to the base e. log10(x) = loge(x)/loge(10)
ln means loge. e is about 2.718281828
ln stands for the function that associates a value with it natural logarithm or, in other words, its logarithm to the base e. You are probably familiar with common or base 10 logarithms and know that, for instance, log10100 = 2 because 100 = 102. ln works in the same way. loge e2 = 2. The value of e is about 2.71828. Therefore, loge 2.71828 ~=1. This function has characteristics that parallel those of base 10 logarithms. You might wish to see the wikipedia page about the natural logarith.
The natural logarithm is calculated to base e, where e is Euler's constant. For any number, x loge(x) = log10(x)/log10(e)
A natural logarithm or a logarithm to the base e are written as: ln(X) as opposed to loge(X)
To which base? To base e (natural logarithms) loge 589 ~= 6.378 To base 10 (common logarithms) log10 589 ~= 2.77 To base 2 (a base I quite like) log2 589 ~= 9.202
If this is a mathematical question, there is no obvious answer. Base 12 digits are normally designated as: 0 to 9, A and B. So E does not have a defind value.
ln() the ln stands for the Latin logarithmus naturali, or natural log in English. loge() is also acceptable but more tedious and rarely used.
If we assume a logarithm to the base e, then it is exactly 1.If we assume a logarithm to the base e, then it is exactly 1.If we assume a logarithm to the base e, then it is exactly 1.If we assume a logarithm to the base e, then it is exactly 1.
in math, ln means natural log, or loge and e means 2.718281828
The natural base, e, 2.718281828..., was selected because the derivatived/dx ex is equal to x. This simplifies many calculations, derivatives, integrals, etc. Additional: This base is used because there is a series (of terms) for powers of (e), therefore, powers of any value can be found just by plugging in values in the series.
Having given no base to your log and not specified natural or common, I assume you are asking if there is a base in which logyb5 = -1, ie is there is a number b such that b-1 = 5?Yes.If you want to know what that base is, then you can work it out:Using:logbx = logax ÷ logabyou can work out the value for b using, say natural logs (base e written loge or usually abbreviated to ln) since we know x=5 and logb5 = -1:-1 = ln 5 ÷ ln b⇒ ln b = -ln 5⇒ b = e-ln 5⇒ b = 1÷ eln 5⇒ b = 1/5Alternatively you can see it straight away:b-1 = 1/b = 5⇒ b = 1/5 = 0.2ie log0.25 = -1