2441 feet per second when fired from the British SMLE rifle. Velocity will vary when fired from rifles with a longer or shorter barrel.
No.
Yes, the bullet fired from a recoiling rifle typically has a greater velocity compared to the rifle itself.
When fired from a .303 rifle, it can travel ABOUT 2.5 miles.
The .303 Enfield rifle can fire a bullet about 2 to 2.5 miles- but is not accurate beyond about 600 meters.
Yes, when a bullet is fired from a rifle, the bullet typically has greater momentum and kinetic energy compared to the rifle. This is due to the bullet's higher velocity and lower mass compared to the rifle.
The .45 caliber bullet is not used in a sniper rifle.
The force exerted on the bullet and the recoil force against the rifleman, are equal to each other (for every action there is an equal and opposite reaction). The bullet has a very small mass, and the rifle/rifleman possess a large mass, force is equal to one half mass times velocity squared, F=m/2*v^2. So velocity of the bullet is the square root of twice force divided by mass, small mass equals large velocity. Another way of looking at this problem is to invoke the law of the conservation of momentum: mass(bullet)*muzzle_velocity(bullet) = mass(rifle)*recoil_velocity(rifle). This is an approximation that neglects the momentum carried away the propellant (both spent and unburned) that exits the muzzle after the bullet.
303 was the .303 inch diameter bullet that was fired by the Short Magazine Lee Enfield- or SMLE. Standard rifle of the British military from 1907 to the1960s, and still in limited use today.
No. The L1A1 Self Loading rifle in in caliber 7.62 x51 mm (7.62 NATO) fires a rimless cartridge with a .308 bullet. The .303 Enfield cartridge is a different shape, has a rim, and fires a .311 bullet. If you compare the two cartridges, totally different in shape.
Bren gun, Lewis gun, SMLE rifle
Before the shot, total momentum of the rifle/bullet system is zero. Momentum is conserved, so must total zero after the shot. Magnitude of momentum = m V (mass, speed); we'll take care of direction independently. Momentum of the rifle: m V = (3.8) x (2.4) = 9.12 kg-m/sec backwards. We need momentum of the bullet = 9.12 kg-m/sec forward m V = 9.12 ===> V = ( 9.12 / m ) = ( 9.12 / 0.013 ) = 701.54 m/s forward
The momentum of the bullet fired from a rifle is greater than the momentum of the rifle's recoil. This is because the bullet has a higher velocity and mass compared to the rifle, resulting in a greater momentum.