18.84 x 1.5
Radius: 18.84/2*pi = about 3 feetVolume: pi*3*3*1.5 = 42.412 cubic feet rounded to three decimal places
Circumference = 33 feet => radius = 33/(2*pi) feet.Then volume = pi*r2*h = pi*[33/(2*pi)]*54/12 cubic feet = 389.97 cu ft = 2429 gallons.
1 cu ft ≈ 6.22884 imp gal ≈ 7.48052 US gal 12 in = 1 ft → 7'4'' = 7+4/12 ft = 7⅓ ft → volume = (6 ft)² × 7⅓ ft = 264 cu ft ≈ 264 × 6.22884 imp gal ≈ 1644 imperial gallons ≈ 264 × 7.48052 US gal ≈ 1975 US gallons
Find the volume of the pool (in cu ft) and multiply by the number of gallons of water per cubic foot. Volume = 9x13x3 = 351 cu ft 351 x 7.481 (gal per cu ft) = 2625.831 gal
We have no idea as you have only specified its length (W ft) and width (9 ft). Depth is a third dimension perpendicular to length and width. If you gave more information, for example the area = length × width of the base rectangle (which in this case is 9 ft × W ft = 9W ft²) then the value of W could be calculated, and if you had also given its volume = length × width × depth, the depth could be calculated by dividing the volume by the area.
Diameter= 60 ft. Radius = 30 f. Depth = 12 ft. Area = PI * r^2 (sq. ft.) = PI*30^2 = 2827.4 sq. ft. Volume = (Area * Depth)/2 (cu. ft.) = 16964.6 cu. ft. =Volume (cu. ft.) * 0.13368 cu.ft./gal >>(gallons) = 126890.6 gallons
Radius: 18.84/2*pi = about 3 feetVolume: pi*3*3*1.5 = 42.412 cubic feet rounded to three decimal places
The volume is that of a cylinder: radius = ½ × diameter volume = π × redius² × height = π × (½ × 3)² × 5 ft³ = 11¼π ft³ ≈ 35.343 ft³ What this is in gallons depends upon the gallon used: 1 ft³ ≈ 6.229 imp gal → 35.343 ft³ ≈ 35.343 × 6.229 imp gal ≈ 220.15 imp gal 1 ft³ ≈ 7.481 US gal → 35.343 ft³ ≈ 35.343 × 7.481 US gal ≈ 264.38 US gal
To find the volume (cu ft), multiply length x width x depth and then multiply the volume by the number of gallons of water per cu ft (7.481): 20 x 9 x 9 = 1620 cu ft x 7.481 = 12,119.22 gallons
7 ft x 2 ft x 2 ft = 28 cu ft 1 cu ft = 7.48052 gal 1 cu ft = 28.3168 L So, the volume of the aquarium is: 209.455 gal = 792.872 L
Simple volume conversion problem. Volume of cylinder = area of circle X height Conversion factor needed = 1 ft^3 = 7.48 gal (6^2 X 3.14 / 4 X 6) ft^3 X 7.48 gal/ft^3 = 1268.95 gal
Circumference = 33 feet => radius = 33/(2*pi) feet.Then volume = pi*r2*h = pi*[33/(2*pi)]*54/12 cubic feet = 389.97 cu ft = 2429 gallons.
17.9 cubic feet.
1 cu ft ≈ 6.22884 imp gal ≈ 7.48052 US gal 12 in = 1 ft → 7'4'' = 7+4/12 ft = 7⅓ ft → volume = (6 ft)² × 7⅓ ft = 264 cu ft ≈ 264 × 6.22884 imp gal ≈ 1644 imperial gallons ≈ 264 × 7.48052 US gal ≈ 1975 US gallons
Find the volume of the pool (in cu ft) and multiply by the number of gallons of water per cubic foot. Volume = 9x13x3 = 351 cu ft 351 x 7.481 (gal per cu ft) = 2625.831 gal
Assuming that 4' if the average depth and the pool is rectangular. Roughly 11,500 gal.
We have no idea as you have only specified its length (W ft) and width (9 ft). Depth is a third dimension perpendicular to length and width. If you gave more information, for example the area = length × width of the base rectangle (which in this case is 9 ft × W ft = 9W ft²) then the value of W could be calculated, and if you had also given its volume = length × width × depth, the depth could be calculated by dividing the volume by the area.