What is the volume of 2.0 moles of an ideal gas at STP?
1 mole of an ideal gas occupies 22.4 liters at STP - so 2 moles occupies 44.8 liters.
At RTP the assumed temperature is 293ºK, at STP the assumed temperature is 273ºK. The formula used for this is Pressure x Volume = moles x ideal gas constant x Temperature. So Volume = (moles x ideal gas constant x temperature) / Pressure Assuming Pressure and moles stays constant... Volume at RTP = ( 1 mole x 8.31451 x 293 K ) / ( 101.325 Pa) Volume at RTP = 24.0429 Volume at RTP =…
Because you're in STP conditions, you can use molar volume in a proportion. Molar volume is the volume one mole of an ideal gas will take up at STP: 22.4 liters/mole. To set up a proportion, think: if one mole of a gas occupies 22.4 liters, then 4.0 moles of a gas will occupy x liters. 1 mole/22.4 L = 4.0 mole/X L x = 44.8 liters