It depends on its date.
The current U.S. dime (1965 to the present) is 0.08 avoirdupois ounce, 7/96 troy ounce (about 0.0792 troy ounce or 2.268 grams).
The U.S. dime from 1873 to 1964 was 2.500 grams (38.58 grains, 0.08038 oz troy, 0.08818 oz avoirdupois).
£1000 in 20s with a bank band weighs 55.0 g so allowing 0.5 g for the band that is 54.4g divided by fifty gives 1.09g each is worth 12.12.12.12.12.12.12.12.12.12.12.1.212.12.12.12.12.12.12.12.12.12.12.12.12..222.222.2 u.s. dollars
The standard weight of a US dime dated 1965 or later is 2.268 grams.
Older silver dimes weigh 2.5 grams.
About 12.lbs. One roll is apparently 113.4 grams and there are 50 rolls in a box.
20 dollars in nickels weighs 2 kilogram, since each 5 cent coin weighs 5 grams and 400 of them equal 20 dollars.
400 nickels weighs 4.41 pounds.
It weighs one pound.
2 grams
The weight of 50 dimes would depend upon when the dimes were minted. For dimes minted from 1873 to 1964 the weight of 50 of them would be 125 grams or 4.02 troy ounces. If the 50 dimes were minted from 1965 to 2009 then the weight of them would be 113.5 grams or 3.65 troy ounces.
2.268 grams. All US Dimes have the same weight.
i dsont know
Balanced force because of the weight of the box
Let 'x' be the total weight of 100 screws in box 'A' therefore, average weight of 100 screws in box 'A' = (x / 100) = 10.4 => x = 100*10.4 = 1040 gms ............ (1) Let 'y' be the total weight of 150 screws in box 'B', therefore, average weight of 150 screws in box 'B' = (y / 150) .......... (2) After mixing 100 screws of 'A' and 150 screws of 'B', average weight of 250 screws = (x+y)/250 = 10.9 => x+y = 250*10.9 = 2725 => 1040+y = 2725 => y = 2725 - 1040 = 1685 => total weight of 150 screws of box 'B', y = 1685 gms Substitute y = 1685 in eqn (2), => average weight of screws of box 'B' = 1685/150 = 11.23 gms (approx) Hence, average weight of screws of box 'B' = 11.23 gms SHORT ANSWER """"""""""""""""" Given data: No. of screws in box 'A', NA = 100 No. of screws in box 'B', NB = 150 Average weight of 100 screws in box 'A', XA = 10.4 gms Average weight of mixed screws, XAB = 10.9 gms Average weight of 150 screws in box 'B', XB = ? Therefore, XAB = (NA XA + NB XB) / (NA + NB) 10.9 = (100*10.4 + 150XB) / (100+150) 10.9 = (1040 + 150XB) / 250 10.9*250 = 1040 + 150XB 2725 = 1040 + 150XB 2725 - 1040 = 150XB 1685 = 150XB XB = 1685/150 = 11.23 gms XB = 11.23 gms - Ratnakar Sharma
15 quarters, 3 dimes
Depends on the size of the box.
Depends on the size of the box.
50
250.00
The weight of 50 dimes would depend upon when the dimes were minted. For dimes minted from 1873 to 1964 the weight of 50 of them would be 125 grams or 4.02 troy ounces. If the 50 dimes were minted from 1965 to 2009 then the weight of them would be 113.5 grams or 3.65 troy ounces.
Armored car services deliver boxes of dimes worth $250. That's fifty $5.00 rolls.
50 rolls of 50 dimes, 2,500 dimes total, face value of $250.
A roll of wrapped dimes weights 4 oz.
you separate a mixture of nickels and dimes by their weight
A kilogram of dimes is worth more because it is larger in weight compared to a pound of dimes. The weight difference between a pound and a kilogram makes the kilogram of dimes more valuable.
Two . Two sixty eight