F(x)=x**2-5*x+2
y-int (where x=0):
0**2-5*0+2 = 2
(0,2)
x-int (where y=0):
0=x**2-5x+2
use quadratic equation
(-(-5)+sqrt((-5)**2-4*1*-5))/2 = 0.5*(5+sqrt(17))
(-(-5)-sqrt((-5)**2-4*1*-5))/2 = 0.5*(5-sqrt(17))
(0.5*(5+sqrt(17)),0),
(0.5*(5-sqrt(17)),0)
The x-intercepts are the points where the graph of the equation intersects the x-axis. To find them, set f(x)=0 and solve for x. For the equation f(x)=x^2-5x+2, you can use factoring or the quadratic formula to find the x-intercepts.
The y-intercept is the point where the graph intersects the y-axis. To find it, substitute x = 0 into the equation f(x)=x^2-5x+2 and solve for f(x).
y = -16x2 + 342At the x-intercepts, y=0-16x2 + 342 = 016x2 = 342x2 = 342/16 = 21.375x = plus and minus sqrt(21.375) = approx. plus and minus 4.6233 (rounded)
x=3 y=2 z=6
An equation where x equals 3.
None because the discriminant of this quadratic equation is less than zero.
x=0
type you answer here!
y = -16x2 + 342At the x-intercepts, y=0-16x2 + 342 = 016x2 = 342x2 = 342/16 = 21.375x = plus and minus sqrt(21.375) = approx. plus and minus 4.6233 (rounded)
x=3 y=2 z=6
An equation where x equals 3.
x = ±2
Yes that is correct
None because the discriminant of this quadratic equation is less than zero.
x=0
Without an equality sign and not knowing the plus or minus values of y and 13 the information given can't be considered to be a straight line equation
It is an equation and the value of n is 9
15x minus 8=minus 180 3x+8=24
By including its plus or minus signs