To calculate the moles of O2 produced, first find the moles of CO2 using its molar mass, which is 44.01 g/mol. Then, use the mole ratio from the balanced equation to find the moles of O2 produced. Finally, multiply the moles of CO2 by the mole ratio to get the moles of O2 produced.
KO2 is rare and is called potassium superoxide. It consists of K+ ion and O^2- ion. In this case, the oxidation number of O would be 1-. If, however, you meant to ask about K2O (potassium oxide), then the oxidation number of O would be 2-
The chemical symbol for superoxide is O2-.
The metal of copper can react with oxygen. This is a metal that is very reactive when ti is combined with different substances.
Chemicals aren't used to make O2 on board modern submarines; they use electrolysis to separate the Hydrogen and Oxygen in DI water, then store the O2 in tanks outside the pressure hull. The hydrogen is bled overboard as tiny bubbles (in the wine.... make me feel happy...make me feel fine).
You would need 18 grams to get the requirement. Using a chemical equation can help to solve this for you.
323.2 grams of KO2 is equal to 4.55 moles of KO2. Per the equation, 3.4125 moles of O2 is produced which is equal to 2.055 E24 molecules of oxygen. This means that every mg of KO2 produces 6.36 E18 molecules of O2.
The chemical formula of potassium superoxide is KO2.
The balanced chemical equation for the reaction would be: 4KO2 + 2CO2 → 2K2CO3 + 3O2 Since the molar ratio between KO2 and O2 is 4:3, 0.400 mol of KO2 would produce: 0.400 mol KO2 * (3 mol O2 / 4 mol KO2) = 0.300 mol O2
Use.PV = nRTTo get moles O2. ( 20.0o C = 293.15 Kelvin )(1.00 atm)(1120.0 L) = (X moles)(0.08206 L*atm/mol*K)(293.15 K)Moles = 1120.0/24.56= 45.60 moles O2-----------------------------------now,45.60 moles O2 (1 mole KO2/2 mole O2)(71.1 grams/1 mole KO2)= 1621 grams potassium oxide required=============================
KO2
To calculate the moles of O2 produced, first find the moles of CO2 using its molar mass, which is 44.01 g/mol. Then, use the mole ratio from the balanced equation to find the moles of O2 produced. Finally, multiply the moles of CO2 by the mole ratio to get the moles of O2 produced.
This question can not be answered because KO2 is not an existing chemical compound and the probable mistaken compound K2O (potassium oxide) does not produce free oxygen (O2) in a normally possible chemical reaction.
The reaction is:4KO2 + 2H2O ---> 4KOH + 3O2
The oxidation number for oxygen (O) in KO2 is -1. Since the overall charge of the compound is 0, the oxidation number of potassium (K) is +1.
when k(potassium)added too(oxygen),it forms ko2(potassium oxide)because one molecule of k is reacted with o which contians always two molecules that means o+o=o2,therefore k+o=ko2 not k2o and there is one more reason that when one metal react with oxygen it forms oxides that is O2
K + o2 = ko2