well, no number goes int 5 or 7 that can also go into 8 or 4.
1 goes into 7 and 5 and 8 and 9 and 6
The HCF of the given numbers is 1
840
The number 1 is the first number that goes into 5 and 8 equally.
well, no number goes int 5 or 7 that can also go into 8 or 4.
the number that goes into 5,7,8 is the number 6
1 goes into 7 and 5 and 8 and 9 and 6
The HCF of the given numbers is 1
840
To find out how many times one number goes into a second number divide the second number by the first number; In this case 56 ÷ 8 = 7.
i may be wrong, but, from the way i see it, it appears that every other number increases by one. so, let's start by viewing the pattern. it goes 5, 7, 6, 8, 7.now if you will notice each number counts up one if you start from the first number and skip one in between. it goes 5 6 7. or to see it within the pattern, 5 7 6 8 7 ? (i will substitute the unknown number for x.)the same pattern happens with the numbers starting from the second one and skipping one in between. it counts up one like 7 8 x(unknown #). also, to see this in the patter, 5 7 6 8 7 x.so from there all you should have to do is follow theh pattern given. it would be eight and progress like this: 5 76 8 7 (9 8 10). (the first # in parenthises should be the one you are looking for.)
The number 1 is the first number that goes into 5 and 8 equally.
' 1 '
3 AND 5
Their LCM is 280
5 7/8