Multiply 630 by .25: 630 * .25 = 157.5
There are infinitely many number pairs: Select any number, X, greater than sqrt(630) = 25.1 Let Y = 630/X Then X*Y = X*(630/X) = 630 Since there are infinitely many numbers greater than 25.1 and X can be any one of them, there are infinitely many possible answers.
18 and 630
Find the numbers that include others in their prime factorization: 7, 9, and 10 Multiply them: 630
630 315,2 105,3,2 35,3,3,2 7,5,3,3,2
3150
630
Multiply 630 by .25: 630 * .25 = 157.5
There are infinitely many number pairs: Select any number, X, greater than sqrt(630) = 25.1 Let Y = 630/X Then X*Y = X*(630/X) = 630 Since there are infinitely many numbers greater than 25.1 and X can be any one of them, there are infinitely many possible answers.
Multiply 63 by 10 is 630
18 and 630
Multiply it by 100 and so it is 630%
Find the numbers that include others in their prime factorization: 7, 9, and 10 Multiply them: 630
The highest common factor of the numbers 490 and 630 is 70.
The GCF of 735 and 630 is 105. To find the GCF of two numbers, you first have to split them into their prime factors. In this case, 735 and 630 can be broken down as follows: 735 = 3x5x7x7 630 = 2x3x3x5x7 The next step is to identify any common prime factors. In this case, both numbers have prime factors of one 3, one 5 and one 7. To find the HCF, we multiply these factors together: 3x5x7 = 105 Thus the GCF of 735 and 630 is 105.
It is: 2*3*3*5*7 = 630
The least common multiple of the numbers 105 and 90 is 630.