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What power is needed to lift a 49kg person a vertical distance of 5.0m in 20.0s?
Wiki User
∙ 11y ago
First, you must find work.
Work is W=FS, F being force (or weight in this case) and S being displacement>
Your force will be the mass of the person (49 kg) times the force of gravity (9.8 m/s^2) When you multiply those two you get 480.2 N as your F.
Plug it into the work formula- W=480.2(5.0).......the 5 m is your displacement. You get 2401 J for work.
Now you can find Power using what we found for work and time which is 20 seconds.
Power=Work/Time, or P=2401/20.
For Power we get 120.05 W (watts)
Wiki User
∙ 11y ago
The power needed is 122.5 Watts. This can be calculated by using the formula: Power = (Force x Distance) / Time. In this case, the force needed to lift the person is the weight of the person, which is equal to mass x gravity, where gravity is 9.8 m/s^2. Then, Power = (49kg x 9.8 m/s^2 x 5.0m) / 20.0s.
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