Zero. The oxidation of one compound must be matched by the reduction of another.
The oxidation numbers of the elements in a compound must add up to zero. This is because in a compound, the overall charge is neutral. The sum of the oxidation numbers helps determine the charge of the compound.
In the compound NaF2, sodium typically has an oxidation state of +1, and fluorine has an oxidation state of -1. When combined in a compound, the total oxidation numbers must add up to zero, but in NaF2 they add up to +2 (-1 for each fluorine and +1 for sodium), which is incorrect. The correct formula should be NaF.
The oxidation number of lead in PbCl2 is +2. This is because chlorine typically has an oxidation number of -1, and since the compound is neutral, the oxidation numbers must add up to zero.
The sum of the oxidation numbers in a neutral compound is always zero. This is because the total charge of the compound is zero, so the sum of the oxidation numbers of the individual elements must also add up to zero.
The oxidation number of silicon (Si) in SiF4 is +4. This is because each fluorine atom in the compound has an oxidation number of -1, and since SiF4 is a neutral compound, the oxidation numbers must add up to zero.
The oxidation numbers of the elements in a compound must add up to zero. This is because in a compound, the overall charge is neutral. The sum of the oxidation numbers helps determine the charge of the compound.
In the compound NaF2, sodium typically has an oxidation state of +1, and fluorine has an oxidation state of -1. When combined in a compound, the total oxidation numbers must add up to zero, but in NaF2 they add up to +2 (-1 for each fluorine and +1 for sodium), which is incorrect. The correct formula should be NaF.
The oxidation number of lead in PbCl2 is +2. This is because chlorine typically has an oxidation number of -1, and since the compound is neutral, the oxidation numbers must add up to zero.
The sum of the oxidation numbers in a neutral compound is always zero. This is because the total charge of the compound is zero, so the sum of the oxidation numbers of the individual elements must also add up to zero.
The oxidation number of silicon (Si) in SiF4 is +4. This is because each fluorine atom in the compound has an oxidation number of -1, and since SiF4 is a neutral compound, the oxidation numbers must add up to zero.
The oxidation number of oxygen in SiO2 is -2. In this compound, silicon is assigned an oxidation number of +4 since it is a representative element in group 14, so the total oxidation numbers must add up to zero for a neutral compound.
The oxidation number of N in NF3 is -3. Each F atom has an oxidation number of -1, and since the overall molecule is neutral, the oxidation numbers must add up to zero, making the oxidation number for N -3.
The oxidation number of sodium (Na) is +1 since it is an alkali metal. The oxidation number of oxygen is typically -2. Since the compound NaIO3 is neutral overall, the oxidation numbers must add up to zero. Therefore, the oxidation number of iodine in NaIO3 is +5.
The oxidation number of manganese in manganese oxide (MnO) is +2. This is because oxygen typically has an oxidation number of -2 and in a neutral compound like manganese oxide, the oxidation numbers must add up to zero. Hence, manganese must be in the +2 oxidation state to balance the -2 oxidation state of oxygen.
In Br₂O₃ (dibromine trioxide), bromine (Br) typically has an oxidation number of +3 because oxygen (O) usually has an oxidation number of -2. Br₂O₃ is a neutral compound, so the sum of the oxidation numbers of each element must add up to zero.
The oxidation number of sulfur in CS2 is -2. In carbon disulfide (CS2), each carbon atom has an oxidation number of +4, which means the two sulfur atoms must have oxidation numbers that add up to -8 to balance the charge of the molecule. Hence, each sulfur atom has an oxidation number of -2.
The oxidation number of H in H3PO4 is +1. In a compound, the oxidation numbers of all the elements add up to the overall charge of the compound, which is 0 in this case. Since the oxidation number of oxygen is typically -2 and there are four oxygen atoms in H3PO4, the oxidation number of hydrogen must be +1 to balance the charge.