To toss a ball straight up so that it takes 4.0 seconds to return to you, it must be thrown at a speed of 19.6 meters per second. This is because it will have a speed of zero at 2.0 seconds, therefore it must have a speed of 19.6 meters per second for gravity's 9.8 meters per second squared to slow it to zero in 2 seconds.
First, determine the height the ball travels using the equation h = (1/2)gt^2, where h is the height, g is the acceleration due to gravity, and t is the time. Since it takes 4 seconds to return to you, the total time for the round trip is 8 seconds (4 seconds up and 4 seconds down). Then, set the height when the ball is released to the height when it returns. Finally, solve for the initial velocity needed to achieve this height in 4 seconds.
-- You want it to rise for 2 s and then fall for 2 s .
-- You know that gravity will decrease its upward speed by 9.8 meters per second
every second that it's in the air.
-- So you have to give it an initial upward speed of 19.6 meters per second in order
for it to continue rising for the first 2 seconds, before it runs out of upward gas.
That's about 43.9 miles per hour as it leaves your hand.
The speed of the ball is greatest when it is thrown upward and decreases as it reaches the peak of its trajectory. The speed continues to decrease as the ball falls back down due to the force of gravity pulling it towards the ground.
To calculate the time it takes for the ball to travel 20 meters, we first convert the speed to m/s: 150 km/h = 41.67 m/s. Then, we use the formula: time = distance/speed. Therefore, the ball takes approximately 0.48 seconds to travel 20 meters.
The ball would continue to move at the same speed as the train in the horizontal direction, but its vertical speed would be affected by gravity. The overall motion of the ball would be a combination of the horizontal motion at the speed of the train and the vertical motion due to gravity.
No, the ball is not in equilibrium because it is in motion. Equilibrium refers to a state where the net force and net torque acting on an object are zero, leading to no overall change in motion. In the case of a ball rolling in a straight line at a constant speed, there is no net force acting on the ball, but it is not in equilibrium as it is in motion.
An example of constant motion is a car driving at a constant speed on a straight road.
The ball would continue to move at the same speed as the train in the horizontal direction, but its vertical speed would be affected by gravity. The overall motion of the ball would be a combination of the horizontal motion at the speed of the train and the vertical motion due to gravity.
a bowling approach is the steps a person takes before actually throwing the ball. the approach is also the area that starts at the end of the ball return up to the foul line.
The ball will be traveling at the same speed when it returns to Earth.
Yes, the ball is undergoing acceleration even if it is moving at a constant speed. This is because its direction is changing as it moves around the circular structure, leading to a continuous change in velocity, which is a form of acceleration known as centripetal acceleration.
The straight ball.
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The velocity of the ball at its highest point is 0 m/s. At the highest point of its trajectory, the ball's vertical velocity slows to 0 before changing direction and starting to fall back down due to the force of gravity.
Speed doesn't matter for fast balls, what matters is if it's going straight or not.
OW! Not long enough!
-- a car on cruise control rolling along at a constant speed on a straight section of highway -- a golf ball or squash ball rolling across the gym floor at a constant speed
stay on the power line keep arm straight stay up tall snap ball at hip fast arm speed turn hip stay on the power line keep arm straight stay up tall snap ball at hip fast arm speed turn hip
speed ball is not avalible in emerald