capacitive reactance is inversely proportional to the capacitance of the capacitor and frequency of the AC line
reactance (in ohms) = 1/(capacitance * frequency)
Reactance (in ohms) = 1/(2 pi * capacitance * frequency). Capacitance is in farads. Frequency is in Hertz (cycles/second). So increasing capacitance or increasing frequency will decrease reactance.
There are two factors that determine and object's kinetic energy. The two main factors are mass and velocity.
The two factors that determine a material's density (such as that of wood) are its mass and volume.
Speed and direction determine velocity
the two factors that determine an object's velocity is SPEED and DIRECTION.By: Arjane Lee Lagasca
Reactance (in ohms) = 1/(2 pi * capacitance * frequency). Capacitance is in farads. Frequency is in Hertz (cycles/second). So increasing capacitance or increasing frequency will decrease reactance.
In the basic configuration, a capacitor is constructed with two parallel conductor plates with a layer of insulating material in between. When the cap is hooked up to the AC power supply, the voltage (v) across the plates and the charge (q) induced on the plates follow this capacitance expression: C = dq/dv or i = C dv/dt, where C is determined by the properties of the insulating material and the geometry of the cap (in the case of the parallel plates, the separation between the two electrodes (t). For the parallel plates, C can be written as (dielectric constant * plate area / t). Electrically, the change in the charge induced on the plates (dq), is directly related to the change in voltage difference (dv) between the two plates, since C is a constant. Theoretically, no energy is lost by charging and discharging the cap with an AC current. When the cap absorbs electrical energy from the power supply, it stores the energy in the electric field in the insulator. When discharging, the cap gives the stored energy back to the circuit -- hence, no energy loss. In a circuit, we use the cap to prolong/smoothen/resist any voltage change in time or to absorb a sudden energy surge (electrostatic discharge and power-line glitches, for example).
1/(2 x 3.142 x f x C) where f is frequency of the supply & C is capacitance in farads. for example mains frequency of 50Hz and capacitor of 1uF = reactance of 3182 ohms. Watts = (volts) squared / reactance = 250 volts sq / 3182 = 19 watts then multiply by time. Other factors involved but just approximation.
DATE: 17-MAY-12 THE CAPACITIVE REACTANCE VARIES INVERSELY WITH THE AMOUNT OF THE PRODUCT OF MAGNITUDE OF THE SUPPLY FREQUENCY, TWICE THE VALUE OF CONSTANT PI AND THE MAGNITUDE OF CAPACITANCE. IN OTHER WORDS, EVERY TIME YOU INCREASE ANY OF THESE FACTORS OR IF SAY YOU FIX THE VALUE OF CAPACITANCE TO SAY 1 MICROFARAD AND OTHER FACTOR (i.e. 2 x PI) AS CONSTANT ALSO, BUT THEN WHEN DOUBLING THE FREQUENCY, SO THEN THE EFFECT TO THE CAPACITIVE REACTANCE WILL BE INVERSELY OR HALVED. THE MORE YOU INCREASE THE FREQUENCY, THE SMALLER THIS VALUE WILL BE. WHICH IN EFFECT ALLOWING MORE HIGH FREQUENCY CURRENT OR VOLTAGE TO PASS THRU THE CIRCUIT. AND THE REVERSE IS TRUE, MEANING ONCE YOU ALLOW LOW FREQUENCY CURRENT, THEN THE CAPAICTIVE REACTANCE WILL INCREASE AS A RESULT. BY FMSJr. / ABU DHABI, UAE
For most parts of electronics is concerned,there are two types of coupling in any alternating current source (AC) circuits: 1)capacitive coupling(Also known as the AC coupling) 2)Inductive Coupling(Also known as the Transformer coupling) Two circuits of different amplification factors and different hybrid parameter values can be merged or coupled by means of a capacitor (capacitive coupling) or an inductor or a transformer (inductive coupling).There are coupling coefficients involved with the transformer.But Capacitor blocks DC and allows AC most of the time.We use ceramic capacitors for this purpose.However never replace the ceramic capacitor with an electrolytic capacitor .Electrolytic capacitors are strictly polar while ceramic capacitors are not.Electrolytic capacitors are used as bypass capacitors.They bypass the current from the resistances that are parallel to them during high frequencies.This is so because the reactance of the capacitor is low at such high frequencies.Also current takes the least resistance path.As reactance gives the AC equivalent of the resistance,current flows into the capacitor while resistance and capacitors are connected end-end and thus the current reaches the other node(its like a diversion or a detour or a shortcut on the road for vehicles-analogously it is the simplest path a current can follow on the conductor
If you mean the capacity of the capacitor then, Factors are:- Area of of overlap of the plates Separation of the plates How good is the insulating material between the plates (the dielectric) If you mean how large a charge can be stored then, Factors are:- The capacitance of the capacitor (C). The applied voltage (V). Charge Q =CxV V cannot exceed the dielectric's breakdown voltage.
Reactance increase means the value of the inductance is already increased because thease two factors are directly proportional to eachother. we can see from the formula ; inductive reactance xL =2(3.14)FL
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Current Flow I believe.
Normal power is the multiplication of current to combination of resistive and reactive or capacitive load. From the vector sum of Apparent power minus real power we can get reactive power(KVAr), which is basically lagging power due to reactive load. This will be the exact rating of capacitor bank. You can find it by cos $ of apparent power.
This question does not make sense. For what use, or what kind, even the size are all factors of a capacitor. Look up the definition of what a capacitor is and then ask a real question.
What are the factors that determine the length of an engagement?