Ionisation in solution is not a chemical reaction. It can be written as one but still it's NOT: only physical change of state ( subscripted between brackets (s) or (aq) )
Na2S(s) --> 2Na+(aq) + S2-(aq)
Both compounds are soluble in water, so they will form a mixture of cations and anions, but there will be no chemical reaction.
Na2S(aq) + 2NaCl(aq) --> 2Na+(aq) + S2-(aq) + 2Cl-(aq) --> no reaction
Synthesis reaction: 2Na + Cl2 --> 2NaCl
Two substances combine to form a more complex substance
double replacement
The reaction Zn + CuCl2 --> Cu + ZnCl2 is a single-replacement reaction.
The reaction between copper (Cu) and hydrochloric acid (HCl) to form copper(II) chloride (CuCl2) and hydrogen gas (H2) is a single displacement reaction. This is because the copper replaces the hydrogen in HCl to form CuCl2.
The chemical reaction equation for lead(II) nitrate (Pb(NO3)2) and sodium sulfide (Na2S) is: Pb(NO3)2 + Na2S → PbS + 2 NaNO3 This reaction forms lead(II) sulfide (PbS) and sodium nitrate (NaNO3) as products.
A single-replacement reaction
This is a redox reaction.
The reaction Zn + CuCl2 --> Cu + ZnCl2 is a single-replacement reaction.
The reaction between copper (Cu) and hydrochloric acid (HCl) to form copper(II) chloride (CuCl2) and hydrogen gas (H2) is a single displacement reaction. This is because the copper replaces the hydrogen in HCl to form CuCl2.
No, there is no reaction/
This is a redox reaction.
The chemical reaction equation for lead(II) nitrate (Pb(NO3)2) and sodium sulfide (Na2S) is: Pb(NO3)2 + Na2S → PbS + 2 NaNO3 This reaction forms lead(II) sulfide (PbS) and sodium nitrate (NaNO3) as products.
No, Na2S(aq) + 2HCl(aq) ®2NaCl(aq) + H2S(g) is a double displacement reaction.
A single-replacement reaction
1. Add a small quantity of the FeCl3 solution into the Na2S(aq.). 2FeCl3+3Na2S=2FeS↓+6NaCl+S↓ the following is the ionic reaction equation 2Fe3+ + S2- = 2FeS↓+ S↓ 2. Add a small quantity of the Na2S solution into the FeCl3(aq.) 2FeCl3 + Na2S =2FeCl2 + 2NaCl + S↓ the following is the ionic reaction equation 2Fe3+ + S2- = S↓ + 2Fe2+
In Na2S, ionic bonds are formed between sodium (Na) and sulfur (S) atoms. Sodium atoms donate electrons to sulfur atoms, resulting in the formation of positively charged sodium ions (Na+) and negatively charged sulfide ions (S2-). These ions are then attracted to each other, forming an ionic bond.
Na2S is a strong base because it completely dissociates in water to form Na+ and S2- ions. When Na2S reacts with an acid, the S2- ion can act as a base and accept a proton from the acid, leading to the formation of HS- ions or H2S gas, depending on the strength of the acid. The reaction between Na2S and an acid results in the neutralization of the acid.
The reaction between copper (Cu) and hydrochloric acid (HCl) is a single displacement reaction, where the copper displaces hydrogen from the acid to form copper(II) chloride (CuCl2) and hydrogen gas (H2). This reaction can be represented as: 2HCl + Cu -> CuCl2 + H2.
The synthesis reaction is.... Cu + Cl2 --> CuCl2