Your question is ambiguous.
Possible answers are:
1. 333 (333 in base 5 = 333 in base 5). You must properly specify an alternate base if you want a conversion between 2 different bases.
2. 2313 (converted 333 base 10 to base 5)
3. 93 (converted 333 base 5 to base 10)
Method:
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If you want to know 333 base 10 value in a base 5 system, then your answer is: 2313.
Base 10 to Base 5 Conversion Method:
333 / 5 = 66.6 .6*5 = 3
66 / 5 = 13.2 .2*5 = 1
13 / 5 = 2.6 .6*5 = 3
2 / 5 = .4 .4*5 = 2
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If you want to know 333 base 5 value in a base 10 system, then your answer is: 93.
Base 5 to Base 10 Conversion Method:
5^2=25 * 3 = 75
5^1= 5 * 3 = 15
5^0=1 * 3 = 3
75 + 15 + 3 = 93
The absolute value of any number is the same number as a positive value. Therefore the absolute value of -333 is +333, or just plain 333.
This question is ambiguous, because an alternate base must be specified if you want a conversion between two different bases. However, assuming that 93 is in the common modern decimal base, 93 = (3 X 52) + (3 X 5) + (3 X 1), so the decimal number 93 would be written as 333 in base 5.
Coefficient -5. Base: x. exponent: 3. Value: depends on the value of x. or Base: (-5)1/3x, exponent: 3
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1000.
The base can have any positive value.
(333) (333) (333) (333) (333) this is five groups of three, could be anything as the three items but hast to have five different groups of it. In total there is 15 of that item.
The base of log, if unspecified, is taken to be 10 so you would be finding the value of the logarithm of 5 to the base 10.This is the value x, such that 10^x = 5.
333
The greatest value a digit can have in base for is 3. Thus the largest three-digit number in base for would be 333. In base 10, this number is 3x16 + 3x4 + 3 = 63 Therefore 63 is the largest digit that would be three digits in base 4.
66.6
4000004