variable c
The relevant equation behind this problem is Q=m*c* ΔT Where Q is the energy that must be added to or taken from the system, m is the mass of the object, c is the objects specific heat, and ΔT is the change in temperature in Celsius or Kelvin. Plugging in the given values we get that Q=.015kg * 128J/(kg*C) * 10C=19.2J. Therefore, you need 19.2 joules of heat in order to raise the temperature of a .015kg sample of lead by 10 degrees Celsius.
Q (heat) = mass*Specific Heat*Temperature differenceI assume 2.5 * 101 Joules? or 25 J & 10 grams of substance?25 J = 10 grams * (SH) * (70-10oC)25 J =10 g *60oC * SHSH = 25 J/(10 g * 60oC)S.H. = 0.0417 J/gOC
0.11cal/g degrees C
It means that it takes more energy to raise the object's temperature by 1 degree than it does to increase the temperature of water by 1 degree..
No. It is a noun: "You've still got your soup on the heat."And a verb: "You still need to heat up your soup."But not an adverb; that modifies a verb, and adjective, or another adverb.
variable c
The variable c
c represents the "specific heat capacity" in which you will have to refer to the chart which lists the different elements' different heat capacities unless indicated by the question.
The specific heat of the substance being heated.
Answer: Thermal Heat. Its Thermal somethingI just passed it and forgot the answer
The unit for the specific heat capacity is J/kg.K.
variable c
The ability of a substance to hold heat.
Q=mc∆T
In the equation Q equals m plus x t plus c, Q represents the total quantity or value being measured or calculated. t represents the variable or time period being observed or measured. c represents the constant term or the y-intercept, which is the value of Q when t equals zero.
That depends what the original equation is.
Probably because somebody wanted, precisely, to find the specific heat.