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What volume of 0.0300 M calcium hydroxide is required to neutralize 34.00 mL of 0.0400 M nitric acid?
Always start with your balanced chemical equation:
2HNO3 + Ca(OH)2 ---> Ca(NO3)2 + 2H2O
The first thing to look for is the acid:base ratio. Here, each molecule of nitric acid produces one H+, but each molecule of Ca(OH)2 has 2 OH-'s. This means that the concentration of HNO3 is going to be twice that of the Ca(OH)2, mathematically,
2Mbase = Macid.
Now the formula for neutralizing acid, where the concentration x volume of the base is equal to the concentration x volume of the acid:
MbVb = MaVa, since the concentration of the HNO3 is twice that of the Ca(OH)2, the formula gets modified to 2MbVb = MaVa. Now we're ready to "plug and chug."
2(0.0300M)Vb = (0.0400M)(34.00mL); and Vb = 22.7mL
What else can I help you with?
What volume of 0.0550 M calcium hydroxide is required to neutralize 35.00 mL of 0.0550 M nitric acid?
To determine the volume of calcium hydroxide needed to neutralize the nitric acid, you can use the equation n1v1=n2v2, where n is the number of moles and v is the volume. As the concentration and volume are given for both the acid and base, the volumes of both solutions needed to neutralize each other will be equal. Therefore, the volume of 0.0550 M calcium hydroxide required will also be 35.00 mL.
What type of reaction is calcium hydroxide plus nitric acid?
The reaction between calcium hydroxide and nitric acid is a neutralization reaction, resulting in the formation of calcium nitrate and water. Calcium hydroxide, a base, reacts with nitric acid, an acid, to form a salt (calcium nitrate) and water.
How many moles of calcium hydroxide are needed to react with 5.88 mL of nitric acid?
To determine the number of moles of calcium hydroxide needed to react with the nitric acid, you would need to know the concentration of the nitric acid. With the concentration, you can use the balanced chemical equation of the reaction to calculate the moles of calcium hydroxide required.
What salt is produced when mixing nitric acid with calcium hydroxide?
The salt produced when mixing nitric acid with calcium hydroxide is calcium nitrate. This reaction also results in the formation of water.
How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
The balanced chemical equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is 1:1 ratio. Therefore, 3 moles of nitric acid will require 3 moles of potassium hydroxide to neutralize it.
What volume of 0.0550 M calcium hydroxide is required to neutralize 35.00 mL of 0.0550 M nitric acid?
To determine the volume of calcium hydroxide needed to neutralize the nitric acid, you can use the equation n1v1=n2v2, where n is the number of moles and v is the volume. As the concentration and volume are given for both the acid and base, the volumes of both solutions needed to neutralize each other will be equal. Therefore, the volume of 0.0550 M calcium hydroxide required will also be 35.00 mL.
What mass of potassium hydroxide is required to neutralize 95.00ml of 0.025m nitric acid?
The answer is o,13 g KOH.
What type of reaction is calcium hydroxide plus nitric acid?
The reaction between calcium hydroxide and nitric acid is a neutralization reaction, resulting in the formation of calcium nitrate and water. Calcium hydroxide, a base, reacts with nitric acid, an acid, to form a salt (calcium nitrate) and water.
How many moles of calcium hydroxide are needed to react with 5.88 mL of nitric acid?
To determine the number of moles of calcium hydroxide needed to react with the nitric acid, you would need to know the concentration of the nitric acid. With the concentration, you can use the balanced chemical equation of the reaction to calculate the moles of calcium hydroxide required.
What salt is produced when mixing nitric acid with calcium hydroxide?
The salt produced when mixing nitric acid with calcium hydroxide is calcium nitrate. This reaction also results in the formation of water.
A nitric acid solution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 3.50L of 0.700 M nitric acid solution?
98g
A nitric acid solution is neutralized using sodium hydroxide how many grams of sodium hydroxide are needed to neutralize 5.50 L of 1.200M nitric acid solution?
262 - 266
How many moles of potassium hydroxide are needed to neutralize 3 moles of nitric acid?
The balanced chemical equation for the reaction between potassium hydroxide (KOH) and nitric acid (HNO3) is 1:1 ratio. Therefore, 3 moles of nitric acid will require 3 moles of potassium hydroxide to neutralize it.
A nitric acid solution is neutralized using sodium hydroxide How many grams of sodium hydroxide are needed to neutralize 5.50 L of 1.200 M nitric acid solution?
262 - 266
What is the molarity of a solution of nitric acid if 0.216 g of barium hydroxide is required to neutralize 20.00 ml of nitric acid?
To calculate the molarity of nitric acid, you need to determine the number of moles of barium hydroxide used in the neutralization reaction. From there, you can use the balanced chemical equation to find the moles of nitric acid present in the solution. Finally, divide the moles of nitric acid by the volume of the solution in liters to find the molarity.
What is pH of result reaction calcium hydroxide and nitric acid?
Calcium nitrate has a neutral solution (pH=7).
What is formed when calcium hydroxide is reacted with dilute nitric acid?
NaOH + HCL --> NaCl + H20 The basic equation is as follows: NaOH(aq) + HCl(aq) -----------> NaCl(aq) + H20(l) sodium hydroxide + hydrochloric acid ----> Sodium chloride + water. The molecules themselves dissociate in an equilibrium and so the ionic equation is: H+(aq) + Cl-(aq) + Na+(aq) + OH-(aq) ---------> Na+(aq) + Cl-(aq) + H2O(l). hope that helps
