Molarity = moles of solute/Liters of solution
Liters of solution = moles of solute/Molarity
Liters NaOH = 3.25 moles NaOH/2.5 M NaOH
= 1.30 Liters NaOH
25m x 6m x 18m = 2,700 cubic m
A cone that has a radius of 20m and a height of 25m has a volume of 10471.98m3
M1V1=M2V2 .5M x ?mL = .25M X 500mL Rearrange it and you get ?mL = (.25M x 500mL) / .5 Which equals 250mL needed of the .5M NaCl.
what is the length of a 25m pool
25m + 22p is in its simplest form.
25m and cm are are not equivalent measures.
150cm/25m = 150cm/2500cm = 0.06
25m is 82 feet 0.25 inches.
This question has no meaning as written. One cannot dilute .75 milliliters (mL) to make a smaller volume of 0.25 milliliters. I suspect that the question should read "What is the volume of water that must be added to 300 mL of .75 M HCl to dilute the solution to 0.25 M?" This is a sensible question. M refers to molarity, or moles per liter. To solve this problem and others like it, use the equation M1V1 = M2V2. M1 = the molarity of the initial/more concentrated solution V1 = the volume of the initial/more concentrated solution M2 = molarity of the second/more dilute solution V2 = volume of the initial/more dilute solution Plug in the known values, rearrange and solve algebraically. For the problem above, this is (M1V1/M2 = V2, or (.75 M)(300 mL)/(.25M) = 224.75 mL needed.
I presume the tunnel has an arch shaped cross-section with a semicircle on top of a rectangle. In this case the volume of the tunnel is the volume of the cuboid bottom plus the volume of half cylinder which forms the top. The volume of the half cylindrical top is ½πr²h = ½ × π × (6m)² × 25m = 450π m³ The volume of the cuboid is length × width × height. The length is 25m. The width is the diameter of the top half cylinder which is twice the radius at 2 x 6m = 12 m. The height is not clear. I am going to presume it is to the top of the arch, so that the height of the cuboid is the height less the radius of the cylinder, namely 7m - 6m = 1m. Thus the volume of the cuboid bit is 25m x 12m x 1m = 300 m³ Thus the volume of the tunnel as a whole is 300 m³ + 450π m³ ≈ 1713.72 m³ (If the 7m height refers to the height of the vertical walls, then the volume of the cuboid is 25m x 12m x 7m = 2100 m³ and the volume of the tunnel is 2100 m³ + 450π m³ ≈ 3513.72 m³.)
The mass of NaCl is 14,61 g.
If the pool is 50m by 25m and is 2m deep then it will have 2,500 kilolitres of water in it. It's volume would be 2,500 metres cubed:) 50m by 25m by 2m is the standard Olympic swimming pool measurement:) hope that helps:)
You dont swim 25m at a competition. The 25m race is not an official race, as an Olympic pool is 50 meters long.
volume = depth x length x width or volume = depth x area Your area is 1m² and your depth is 25cm or 0.25 m so.... Volume = .25m x 1m² = .25 m³
percentage = 24%% rate:= 6m/25m * 100%= 0.24 * 100%= 24%
I think you're describing a swimmimg pool that's square, 25 meters on each side,and 4 feet deep. I hope I'm reading that correctly.The volume of that pool is (25m x 25m x 4-ft) = 26,909.8 cubic feet = 201,299.12 gallonsThat's the volume of the pool. I have no way to know how much water may be in it.
Volume = L*W*DVolume = 25m*13m*1.2m = 390m31 m3 = 1000 L, so 390*1000 = 390,000 L
The question itself is already in meters so there's no need for conversion factors.The formula of a volume is length x width x height.v=lwhjust plug in what you have..25m=length6.1m=width4.9m=heightv=(.25m)(6.1m)(4.9m)v=7.5m^3The answer is approximately 7.5 cubic meters.
Effective range is about 25m
A circumference of 78.54m
You can solve this mathematically by the following: 1.5 km X 1000m/km X 1lap/25m= 60 laps.
Your Marlin model 25M which was made from 1989-2003 will bring between 65-105 dollars depending on overall condition and a good bore.
are you kidding?? 25 meters
25 meters is 82.02 feet.
25 metres / 0.3048 = 82.02ft