The mass shouldn't make any difference in an ideal system.
Using v^2=u^2+2as for each object, you get v=sqrt(2gH) and sqrt(2gh) for the two objects. The ratio will simplify to sqrt(H/h).
Galileo's experiment to show that mass had little effect on the speed of falling objects involved two cannonballs of different sizes being dropped from a certain height. This showed that, in a vacuum at least, falling objects fall at the same speed no matter their mass.
I wasn't there, so I have no knowledge of how things were set up in that particular experiment. The only force I'm sure of is the force of gravity, and your use of the term "dropped" seems to confirm that assumption.
Action and reaction forces act simultaneously. For every action force, there is an equal and opposite reaction force acting on a different object. This principle is known as Newton's third law of motion.
Orbital velocities of celestial bodies are the speeds at which they move around a central object, like a star or planet. These velocities are determined by the gravitational force between the objects and are necessary for maintaining stable orbits. The orbital velocity of a celestial body depends on its distance from the central object and the mass of the central object.
No, dropping two objects of different mass from the same height doesn't contradict Newton's 2nd Law. The law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass, so objects of different mass will experience different accelerations due to gravity even when dropped from the same height.
The equation for elastic collision is: m1u1 m2u2 m1v1 m2v2 where: m1 and m2 are the masses of the two objects u1 and u2 are the initial velocities of the two objects v1 and v2 are the final velocities of the two objects This equation is used to calculate the final velocities of two colliding objects by taking into account their masses and initial velocities. By solving for v1 and v2, we can determine how the velocities of the objects change after the collision while conserving momentum and kinetic energy.
No because 'g' is irrespective of the object's mass.
The elastic collision equation used to calculate the final velocities of two objects after they collide is: m1u1 m2u2 m1v1 m2v2 where: m1 and m2 are the masses of the two objects, u1 and u2 are the initial velocities of the two objects before the collision, and v1 and v2 are the final velocities of the two objects after the collision.
All objects dropped from the same height will hit the ground at the same time, regardless of their mass or shape, as long as air resistance is negligible. Thus, the marble, textbook, and flaming stick will hit the ground simultaneously.
Yes, two objects of the same mass dropped at different heights will have different speeds when they hit the ground due to the influence of gravity. The object dropped from a higher height will have a higher speed upon impact because it had more time to accelerate while falling.
The physics elastic collision equations used to calculate the final velocities of two objects after they collide are: Conservation of momentum: m1u1 m2u2 m1v1 m2v2 Conservation of kinetic energy: 0.5m1u12 0.5m2u22 0.5m1v12 0.5m2v22 Where: m1 and m2 are the masses of the two objects u1 and u2 are the initial velocities of the two objects v1 and v2 are the final velocities of the two objects
Objects of different masses will reach the ground at the same time when dropped from the same height because they are subject to gravity, which accelerates all objects at the same rate regardless of their mass. This is known as the equivalence principle and was famously demonstrated by Galileo.
The combining of velocities is known as velocity addition or relative velocity. It involves adding or subtracting the velocities of two objects moving relative to each other.
Peculiar velocities are the individual speeds at which celestial objects move within a larger system, like a galaxy or galaxy cluster. These velocities can cause objects to deviate from the overall motion of the system, leading to variations in their trajectories and positions. This can impact the interactions between celestial objects and influence their overall motion within the system.
In an elastic collision, the final velocities of two objects can be calculated using the equations: (v1f fracm1 - m2m1 m2 cdot v1i frac2m2m1 m2 cdot v2i) (v2f frac2m1m1 m2 cdot v1i fracm2 - m1m1 m2 cdot v2i) where: (v1i) and (v2i) are the initial velocities of the two objects, (v1f) and (v2f) are the final velocities of the two objects, and (m1) and (m2) are the masses of the two objects.
Two objects dropped at the same time strike the ground at the same time because they both experience the same acceleration due to gravity, regardless of their masses. This acceleration causes them to fall at the same rate, leading them to hit the ground simultaneously.
In an elastic collision, the final velocity of two objects can be calculated using the conservation of momentum and kinetic energy principles. The final velocities depend on the masses and initial velocities of the objects involved in the collision.