answersLogoWhite

0


Best Answer

Boron has 3 valence electrons, which allows it to covalently bond to three other atoms. Each of the 3 covalent bonds has a pair of valence electrons, which means boron is sharing a total of six valence electrons in a compound. Boron still prefers an octet. Therefore, Boron can share a fourth bond which means boron will share 8 valence electrons, a full octet. But in this case, boron will have a formal charge: 3 valence - 4 bonds = -1 charge. The structure with 4 covalent bonds is similar to carbon (think CH4), but because boron has one less proton than carbon, boron carries a negative formal charge when boron fills its octet by covalently bonding

to 4 atoms.

An example of this would be the acid-base reaction:

BF3 + diethyl ether (C2H5)2O

The oxygen will use one of its lone pair of electrons to form a covalent bond with boron.

This means boron has a minus one formal charge and has 3 bonds (with 3 fluorines)

and one bond to oxygen. The oxygen now is sharing one of its lone pairs in a covalent

bond, so the oxygen has a plus one formal charge now: 6-3-2=+1.

User Avatar

Wiki User

13y ago
This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What would happen for boron to have a full octet?
Write your answer...
Submit
Still have questions?
magnify glass
imp