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Then the angle of refraction would also be 0, and the reflected wave would return along the same path as the incident ray.

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Q: What would happen if the angle of incidence was 0?
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What is the difference of angle of incidence ad the angle of reflection?

0(zero) Angle of incidence = angle of reflection


What is 0 degree incidence?

when a ray of light falls normally ie. perpendicular to the refracting or reflecting ,the the angle of incidence is zero(angle of incidence is the angle between the incident ray and the normal at the point of incidence) A ray with 0 angle of incidence doesnot suffer any change on refraction and goes straight into the second medium.


What is the seize of the angle of refraction if the angle incidence is 0 degrees?

The answer is zero. (From Snell's law, if AI in the angle of incidence, AR is the angle of refraction, and n is the refractive index of the material doing the refracting, then: AR = arcsin[(1/n)sin(AI)] =0 if AI=0.


What is the angle of incidence when a ray falls normally on a mirror?

0 degrees


Is snell's law true when angle of incidence is angle 0 degree?

Yes; if angle of incidence is zero angle of refraction is zero regardless of index: sin theta r = (n1/n2) sin theta i


What is the angle of incidence when a ray of incident normally on a plane mirror?

It is 0 degrees.


When a ray of light passes from air to glass for what angle of incidence the ray will not be deviated?

Angle of incidence has to be 0. This means that the ray has to hit normally on the surface of separation of two media


Why light ray does not change it path when fall prallel to the normal?

The angle of incidence would be 90 degrees, so the angle of refraction is 0 degrees, as the light ray does not deviate.


What is an angle of incidence?

The smallest possible angle of incidence for a light ray traveling toward a mirror is 1800. This is because then, the light ray will be either parallel or on the principal axis and hence, the angle of incidence would be 00.


Why does not a light refracts at 90 degrees?

You mean that as light is incident normally. Here the angle of incidence will be 0. As per Snell's law sine of angle of incidence / sine of angle of refraction = refractive index So Sin i = mu * sin r As i=0 then r too has to be 0 as mu is not equal to 0 Hence no refraction becomes possible for a normally incident light ray


Why the ray of light does not bend when it passes perpendicularly from rarer medium to denser medium?

Since the angle of incidence is 0, there is no chance of refraction and so the angle of refraction too becomes 0.


The angle of incedence is equal to the angle of reflection?

This is the second law of reflection phenomenon. So if a ray falls normally on the reflecting mirror then the angle of incidence will be 0. So as the angle of reflection also is to be 0, the ray just retraces its path. That is it is coming back in the same straight line.