1 mol Pb = 207.2 grams
12.4 mol Pb = ? grams (cross multiplication)
mass of (12.4 mol Pb) = (207.2 gr *12.4 mol) / (1mol)
= 2569.28 g
n=? m=121.0g
M=207.2
n=m/M
=0.584 mol (3 sig. fig.)
moles of lead = sample mass/molar mass
2.3456 grams lead (1 mole Pb/207.2 grams) = 0.01132 moles of lead =================
To determine the number of atoms of chlorine in 445g of lead chloride (PbCl2), you need to calculate the number of moles of PbCl2 in 445g and then multiply it by the number of chlorine atoms in one PbCl2 molecule. First, calculate the number of moles of PbCl2 using the formula: moles = mass / molar mass. The molar mass of PbCl2 is 278.1 g/mol, so moles = 445g / 278.1 g/mol = 1.6 moles. Since there are two chlorine atoms in one molecule of PbCl2, the total number of chlorine atoms is 2 * 1.6 moles = 3.2 moles of chlorine atoms. To convert moles to atoms, multiply by Avogadro's number. Therefore, there are 3.2 moles * 6.022 x 10^23 atoms/mole = 1.9264 x 10^24 atoms of chlorine in 445g of PbCl2.
molar mass =207.2 g / mol no. moles = mass/ molar mass moles = 1 1(207.2) = mass mass of 1 mole lead is 207.2g molar mass =207.2 g / mol no. moles = mass/ molar mass moles = 1 1(207.2) = mass mass of 1 mole lead is 207.2g
There are 2.49 x 10^-12 moles of lead in that sample.
Divide the number of grams by the density (the density of lead is about 11 grams/cubic centimeter - look it up if you need more precision). If the density is in grams/cubic centimeter, the answer is the volume in cubic centimeters.
2.3456 grams lead (1 mole Pb/207.2 grams) = 0.01132 moles of lead =================
you calculate the number of moles by working out the gram formula mass of Lead II iodide, which should be 461.03 g/mol, and divide that by the measured ammound of substance you have in grams. That will give you the number of moles of substance you have.
If 17,4 is grams the number of moles is 0,084.
5 moles of lead is equal to 1 036 g.
For this you need the atomic mass of Pb. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel..0015 moles Pb × (207.2 grams) = .311 grams Pb
Atomic mass: 207.2 grams.455 moles × (6.02 × 1023) = 2.74 × 1023 atoms of lead
1,4 moles of lead(II) oxide are formed.
A lot! 9.51 X 103 grams Pb (1 mole Pb/207.2 grams) = 45.9 moles of lead ===============
Using the formula number of moles = mass divided by molar massso mass = number of moles X molar massFind molar mass by adding up the masses of all the atoms in your substance.A good way to remember this is as the formula g/mw = moles, and the mnemonic for this is"Mine workers (mw= molecular weight) under ground (grams of compound you are dealingwith = Moles!
Pb molecular weight is 207.2 g/mol. 33.3 moles of Pb weighs 6899.76 grams.
Mole times Lead's Molecular mass(Mr) gives you its mass And I think the Mr of Lead is 207
umber of Moles= Molar Mass (in g/mol) Mass (in grams) β First, you'll need to know the molar mass of the substance in question. Here are the calculations for each sample: 6.684e13 pg of fluorine atoms: Molar mass of fluorine (F) = 19 g/mol Mass in grams = 6.684e13 pg = 6.684e-6 g Number of moles = (6.684e-6 g) / (19 g/mol) β 3.52e-7 moles 2.435e6 mg of magnesium: Molar mass of magnesium (Mg) = 24.305 g/mol Mass in grams = 2.435e6 mg = 2.435 g Number of moles = (2.435 g) / (24.305 g/mol) β 0.1001 moles 3.2e-3 kg of lead(II) chloride: Molar mass of lead(II) chloride (PbClβ) = 207.2 g/mol Mass in grams = 3.2e-3 kg = 3200 g Number of moles = (3200 g) / (207.2 g/mol) β 15.45 moles 6.684e-5 Mg of fluorine: Molar mass of fluorine (F) = 19 g/mol Mass in grams = 6.684e-5 Mg = 6.684e-5 g Number of moles = (6.684e-5 g) / (19 g/mol) β 3.52e-6 moles 2.31e-9 Gg of carbon disulfide: Molar mass of carbon disulfide (CSβ) = 76.143 g/mol Mass in grams = 2.31e-9 Gg = 2.31e15 g Number of moles = (2.31e15 g) / (76.143 g/mol) β 3.03e12 moles 4.91e9 ng of aluminum sulfate: Molar mass of aluminum sulfate (Alβ(SOβ)β) = 342.15 g/mol Mass in grams = 4.91e9 ng = 4.91e-6 g Number of moles = (4.91e-6 g) / (342.15 g/mol) β 1.43e-8 moles