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1 mol Pb = 207.2 grams

12.4 mol Pb = ? grams (cross multiplication)

mass of (12.4 mol Pb) = (207.2 gr *12.4 mol) / (1mol)

= 2569.28 g

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βˆ™ 11y ago
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βˆ™ 14y ago

n=? m=121.0g
M=207.2


n=m/M
=0.584 mol (3 sig. fig.)

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βˆ™ 7y ago

moles of lead = sample mass/molar mass

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Q: Calculate the number of grams of lead Pb in 12.4 moles of lead?
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How many moles of Pb are in 2.3456g of Pb?

2.3456 grams lead (1 mole Pb/207.2 grams) = 0.01132 moles of lead =================


How many atoms of chlorine are there in 445g of lead 2 chloride?

To determine the number of atoms of chlorine in 445g of lead chloride (PbCl2), you need to calculate the number of moles of PbCl2 in 445g and then multiply it by the number of chlorine atoms in one PbCl2 molecule. First, calculate the number of moles of PbCl2 using the formula: moles = mass / molar mass. The molar mass of PbCl2 is 278.1 g/mol, so moles = 445g / 278.1 g/mol = 1.6 moles. Since there are two chlorine atoms in one molecule of PbCl2, the total number of chlorine atoms is 2 * 1.6 moles = 3.2 moles of chlorine atoms. To convert moles to atoms, multiply by Avogadro's number. Therefore, there are 3.2 moles * 6.022 x 10^23 atoms/mole = 1.9264 x 10^24 atoms of chlorine in 445g of PbCl2.


The molar mass of a mole of lead?

molar mass =207.2 g / mol no. moles = mass/ molar mass moles = 1 1(207.2) = mass mass of 1 mole lead is 207.2g molar mass =207.2 g / mol no. moles = mass/ molar mass moles = 1 1(207.2) = mass mass of 1 mole lead is 207.2g


How many moles of lead are in 1.50 x 1012 atoms of lead?

There are 2.49 x 10^-12 moles of lead in that sample.


What is the volume of a 17.6 grams sample of lead?

Divide the number of grams by the density (the density of lead is about 11 grams/cubic centimeter - look it up if you need more precision). If the density is in grams/cubic centimeter, the answer is the volume in cubic centimeters.

Related questions

How many moles of Pb are in 2.3456g of Pb?

2.3456 grams lead (1 mole Pb/207.2 grams) = 0.01132 moles of lead =================


When the mass of lead II iodide precipitate is measured how is it converted into moles of lead II iodide?

you calculate the number of moles by working out the gram formula mass of Lead II iodide, which should be 461.03 g/mol, and divide that by the measured ammound of substance you have in grams. That will give you the number of moles of substance you have.


How many moles are present in 17.4 of lead?

If 17,4 is grams the number of moles is 0,084.


How many grams of 5 moles of lead?

5 moles of lead is equal to 1 036 g.


How many grams of lead are there in 0.0275 moles of lead?

For this you need the atomic mass of Pb. Take the number of moles and multiply it by the atomic mass. Divide by one mole for units to cancel..0015 moles Pb × (207.2 grams) = .311 grams Pb


How many atoms are in 0.455 moles of lead?

Atomic mass: 207.2 grams.455 moles × (6.02 × 1023) = 2.74 × 1023 atoms of lead


What are the moles of lead II oxide formed when 463.4 grams lead II nitrate is heated on heat?

1,4 moles of lead(II) oxide are formed.


How many moles of Pb are equivalent to 9.51 times 103 g Pb?

A lot! 9.51 X 103 grams Pb (1 mole Pb/207.2 grams) = 45.9 moles of lead ===============


How do you convert 5.2 moles of lead to grams?

Using the formula number of moles = mass divided by molar massso mass = number of moles X molar massFind molar mass by adding up the masses of all the atoms in your substance.A good way to remember this is as the formula g/mw = moles, and the mnemonic for this is"Mine workers (mw= molecular weight) under ground (grams of compound you are dealingwith = Moles!


Grams in 33.3 moles of lead?

Pb molecular weight is 207.2 g/mol. 33.3 moles of Pb weighs 6899.76 grams.


How many grams of lead are in 4.62 moles of lead?

Mole times Lead's Molecular mass(Mr) gives you its mass And I think the Mr of Lead is 207


Calculate the number of moles present in each of the following samples.6.684e13 pg of fluorine atoms 2.435e6 mg of magnesium 3.2e-3 kg of lead(II) chloride 6.684e-5 Mg of fluorine 2.31e-9 Gg of carbon disulfide 4.91e9 ng of aluminum sulfate?

umber of Moles= Molar Mass (in g/mol) Mass (in grams) ​ First, you'll need to know the molar mass of the substance in question. Here are the calculations for each sample: 6.684e13 pg of fluorine atoms: Molar mass of fluorine (F) = 19 g/mol Mass in grams = 6.684e13 pg = 6.684e-6 g Number of moles = (6.684e-6 g) / (19 g/mol) β‰ˆ 3.52e-7 moles 2.435e6 mg of magnesium: Molar mass of magnesium (Mg) = 24.305 g/mol Mass in grams = 2.435e6 mg = 2.435 g Number of moles = (2.435 g) / (24.305 g/mol) β‰ˆ 0.1001 moles 3.2e-3 kg of lead(II) chloride: Molar mass of lead(II) chloride (PbClβ‚‚) = 207.2 g/mol Mass in grams = 3.2e-3 kg = 3200 g Number of moles = (3200 g) / (207.2 g/mol) β‰ˆ 15.45 moles 6.684e-5 Mg of fluorine: Molar mass of fluorine (F) = 19 g/mol Mass in grams = 6.684e-5 Mg = 6.684e-5 g Number of moles = (6.684e-5 g) / (19 g/mol) β‰ˆ 3.52e-6 moles 2.31e-9 Gg of carbon disulfide: Molar mass of carbon disulfide (CSβ‚‚) = 76.143 g/mol Mass in grams = 2.31e-9 Gg = 2.31e15 g Number of moles = (2.31e15 g) / (76.143 g/mol) β‰ˆ 3.03e12 moles 4.91e9 ng of aluminum sulfate: Molar mass of aluminum sulfate (Alβ‚‚(SOβ‚„)₃) = 342.15 g/mol Mass in grams = 4.91e9 ng = 4.91e-6 g Number of moles = (4.91e-6 g) / (342.15 g/mol) β‰ˆ 1.43e-8 moles