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Not sure why it is 3a2- if you mean 3*a*2, then:
3*a*2=6a
(6a-2a)+5-2(a (or a2)+a)=1
4a+5-(2a+a)=1
4a+5-2a-a=1
Then take the 5 over (remember, the +5 become -5 when transposed):
4a-2a-a=1-5
Solving the equations on both sides gives:
a=-4
Is this your answer?
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∙ 13y ago
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When a2 plus a-3 is subtracted from 3a2-5 the answer is?
5a+3a2a2= 8a a2
Why is the Pythagorean therm a2 plus b2 equals c2 not a plus b equals c?
l a2 b2 is c2!!Its completely norma
If a plus b plus c equals x plus y plus z then prove a2 plus b2 plus c2 equals x2 plus y2 plus z2?
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
If 2 plus 3 equals 10and 7 plus 2 equals 63and 6 plus 5 equals 66and 8 plus 4 equals 96 then 9 plus 7 equals?
144 Formula: c= (a2)+(ab)
What is the algebraic formula for a2 plus b2 equals c2?
You just typed it.
When a2 plus a-3 is subtracted from 3a2-5 the answer is?
5a+3a2a2= 8a a2
If a2 plus b2 equals c2 then c2 equals b2 equals?
a2
Why is the Pythagorean therm a2 plus b2 equals c2 not a plus b equals c?
l a2 b2 is c2!!Its completely norma
A2 plus 3 equals 12?
a=3
A2 plus b2 equals c2 is an example of?
Pythagorean Theorem
If a2 plus b2 equals c2 then the triangle is?
a right triangle
If a plus b plus c equals x plus y plus z then prove a2 plus b2 plus c2 equals x2 plus y2 plus z2?
a2+b2+c2=x2+y2+z2 divide each side by 2 (a2+b2+c2)/2=(x2+y2+z2)/2 a+b+c=x+y+z
If 2 plus 3 equals 10and 7 plus 2 equals 63and 6 plus 5 equals 66and 8 plus 4 equals 96 then 9 plus 7 equals?
144 Formula: c= (a2)+(ab)
What is the algebraic formula for a2 plus b2 equals c2?
You just typed it.
Solve a2 plus 30a plus 56 equals 0?
a2+30a+56=0 , solve for a Using the quadratic formula, you will find that: a=-2 , a=-28
What should be subtracted from a2 -4a2 plus 5a2-6 to obatain a2-2a plus 1?
If I've read your question correctly, you need to subtract: a2 +2a -7 a2 -4a2 +5a2 -6 = 2a2 -6 Note, if x - y = z, then y = x - z; so: 2a2 -6 - (a2 -2a +1) = 2a2 -6 - a2 +2a -1 = a2 +2a -7
What is the reciprocal of a plus bi if a2 plus b2 equals 1?
The reciprocal of a + bi is a - bi:1/(a + bi) since the conjugate is a - bi:= 1(a - bi)/[(a + bi)(a - bi)]= (a - bi)/[a2 - (b2)(i2)] since i2 equals to -1:= (a - bi)/(a2 + b2) since a2 + b2 = 1:= a - bi/1= a - bi
