This question can be rather easily answered,
as soon as outcomes 'a' and 'b' are defined.
The probability of tossing two heads in two coins is 0.25.
The probability is 3/4.
50%
These are all independent events. So the probability of them all happening is the product of the probabilities of each one of them happening. The desired probability is (2/6)*(1/2)*(1/2)=1/12
6/16 = 3/8
1 chance in 4
The probability of getting two tails in the first two is 1/4. And it does not matter how many more times the coins are tossed after the first two tosses.
The probability that both coins are heads is the probability of one coin landing heads multiplied by the probability of the second coin landing heads: (.5) * (.5) = .25 or (1/2) * (1/2) = 1/4
2/9
Sample space for two coins tossed is: HH HT TH TT Therefore at most one head is HT TH TT or 3/4 or 0.75.
It is 1/12.
is it 50% or 100% dang, i just confused myself. what if you toss 3 coins all at the same time... what's the probability of getting a head then, is it > 100% ? Doh!