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Lead(II) nitrate and sodium iodide undergo a double displacement reaction to form sodium nitrate and lead(II) iodide, which is a slightly soluble yellow solid. The balanced chemical equation for this reaction is: Pb(NO3)2(aq) + 2NaI(aq) -> 2NaNO3(aq) + PbI2(s)

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When lead nitrate solution is added to sodium iodine solution solid lead iodide is formed word equation?

Aqueous lead nitrate plus aqueous sodium iodide produce solid lead iodide and aqueous sodium nitrate.


Balance Equation.When an aqueous solution of lead II nitrate is mixed with an aqueous solution of sodium iodide an aqueous solution of sodium nitrate and a yellow solid lead iodide are formed?

Pb(NO3)2(aq)+2NaI(aq)=2NaNO3(aq)+PbI2(s)


What is the liquid left when you mix potassium iodide and led nitrate?

potassium nitrate would be left was an aqueous solution and lead iodide would be the precipitate


What is formed in the reaction ki aq agno3 aq agis kno3 aq?

a precipitate. motha nacha -.0


What is formed when silver nitrate is added to sodium iodine?

When aqueous solutions of silver nitrate and sodium iodide [note correct spelling] are mixed, silver iodide solid precipitates from the mixture.


What is the test for hydrogen iodide?

Hydrogen iodide can be tested using silver nitrate solution. When hydrogen iodide is bubbled through silver nitrate solution, a yellow precipitate of silver iodide is formed. This confirms the presence of iodide ions in the sample.


When potassium iodine solution is added to a solution of lead nitrate in a test tube what will be the compound precipitate?

The compound precipitate formed when potassium iodide is added to a solution of lead nitrate is lead iodide, which is a yellow precipitate. This reaction is a double displacement reaction where the potassium ion and nitrate ion switch partners to form potassium nitrate and lead iodide.


What aqueous solution would form a precipitate when mixed with NaI?

Silver nitrate for example: AgI(s) silver iodide


Silver nitrate and strontium iodide?

When silver nitrate and strontium iodide react, a double displacement reaction occurs. Silver iodide and strontium nitrate are formed as products. Silver iodide is a yellow precipitate while strontium nitrate remains in solution.


What happens when a solution of potassium iodide is added to a solution of lead nitrate taken in a test tube?

A yellow precipitate of lead iodide is formed due to the reaction between potassium iodide and lead nitrate. This reaction is a double displacement reaction, where the potassium from potassium iodide swaps places with the lead from lead nitrate, forming the insoluble lead iodide.


What is observed when a solution of potassium iodide is added to lead nitrate name the type of reaction solution?

When a solution of potassium iodide is added to lead nitrate, a yellow precipitate of lead iodide is formed. This is a double displacement reaction where the cations and anions switch partners to form the products.


Lead nitrate is treated with potassium iodide solution?

A precipitate of Lead iodide and Potassium nitrate are formed