If the forces are in the same direction, add them and if they're in opposite directions, subtract them. I'm not sure what to do if they're in directions other than that.
An object at rest. Actually that's the only possible example for a single object. For two objects, you can have objects moving in opposite directions; for example, one may have a momentum of +100 units, and the other, a momentum of -100 units.
Momentum = M V = 100 kg-m/s
Momentum = M V = 100 kg-m/s
momentum is mass x velocity. If mass is 1 kg and velocity 1m/s then momentum is 1kgm/s
Yes. Momentum is based on mass and velocity, not physical size. 1 kg of styrofoam moving at 100 m/s has the same momentum as 1 kg of gold moving at 100 m/s, but the piece of styrofoam will be over 1000 times the size. Additionally, since the formula for momentum is mass times velocity, a 10 kg piece of gold moving at 10 m/s has the same momentum as a 1 kg piece of gold moving at 100 m/s. They both have a momentum of 100 kg-m/s.
We have to assume that both bodies are initially moving along the same straight line in opposite directions, so the collision is "head on". We also have to assume that the collision is "elastic", meaning that none of the original kinetic energy is lost to heat. The final momentum is 20 Kg-m/s in the direction opposite to the original 80 kg-m/s motion.
An object at rest. Actually that's the only possible example for a single object. For two objects, you can have objects moving in opposite directions; for example, one may have a momentum of +100 units, and the other, a momentum of -100 units.
Momentum = M V = 100 kg-m/s
Momentum = M V = 100 kg-m/s
momentum is mass x velocity. If mass is 1 kg and velocity 1m/s then momentum is 1kgm/s
Yes. Momentum is based on mass and velocity, not physical size. 1 kg of styrofoam moving at 100 m/s has the same momentum as 1 kg of gold moving at 100 m/s, but the piece of styrofoam will be over 1000 times the size. Additionally, since the formula for momentum is mass times velocity, a 10 kg piece of gold moving at 10 m/s has the same momentum as a 1 kg piece of gold moving at 100 m/s. They both have a momentum of 100 kg-m/s.
100 Kg m/s
50 Force = ma = m(v-u)/t = (mv – mu)/t = change of momentum /time = rate of change of momentum Momentum of an object changes from 100 kgm/s to 200 kgm/s in 2 seconds. What is the force applied on it? Initial momentum, p1 = 100kg-m/s Final momentum, p2= 200kg-m/s Time,t= 2 s Force,F = ? Using the formula, F= p2-p1/t F= 200-100/2 F= 100/2 F= 50 N The force applied is of 50 N.
100 Kg-m/s
Momentum = speed multiplied to mass. M'm = 5 ms^-1 X 20 kg . M'm = 100 kg m s^-1
Momentum = Mass * Velocity, so all you have to do is multiply those numbers together. 20 kg * 5 m/s = 100 kg*m/s.
The radiation is being totally reflected.The object is absorbing momentum from the radiation, and is experiencinga force ... being 'pushed' ... in the direction that the radiation was travelingbefore the bounce.I'm not making that up.