Initial velocity is 10 m/s in the direction it was kicked.
Final velocity is 0, when friction and air resistance finally causes it to come to a halt.
You can't.You only know what half the sum of (initial + final) is, (it's the average), but you don't know what the initial and final are.
Suppose the two masses are m1 and m2. Their initial velocities are u1 and u2 and final velocities are v1 and v2. Then, using conservation of momentum. m1*u1 + m2*u2 = m1*v1 + m2*v2 Both m1 and m2 are given. Their initial velocities u1 and u2 are given and one of the two final velocities v1 and v2 is given which leaves only one unknown. So substitute all those values and calculate away.
Well, (final velocity) = (initial velocity) + (acceleration x time)
Boyle's Law P1*V1 = P2*V2, where:P1 = initial pressureV1 = initial volumeP2 = final pressureV2 = final volumeCharles' LawV1/T1 = V2/T2, where:V1 = initial volumeT1 = initial temperatureV2 = final volumeT2 = final temperatureGay-Lussac's LawP1/T1 = P2/T2, where:P1 = initial pressureT1 = initial temperatureP2 = final pressureT2 = final temperatureCombined Gas Law(P1*V1)/T1 = (P2*V2)/T2, where:P1 = initial pressureV1 = initial volumeT1 = initial temperatureP2 = final pressureV2 = final volumeT2 = final temperatureIdeal Gas LawPV = nRT, where:P = pressureV = volumen = number of moles of gasR = 0.0821 L*atm/mol*K OR 8.315 dm^3*kPa/mol*KT = temperature
the formula for finding acceleration is final velocity, minus initial velocity, all over time. So if you have the acceleration and initial speed, which is equal to the initial velocity, you must also have time in order to find the final velocity. Once you have the time, you multiply it by the acceleration. That product gives you the difference of the final velocity and initial velocity, so then you just add the initial velocity to the product to find the final velocity.
If you have a particle with constant acceleration, and you add the initial and final velocities and then divide them by two, what you get is the average velocity of the particle in that period of time.
You can't.You only know what half the sum of (initial + final) is, (it's the average), but you don't know what the initial and final are.
Suppose the two masses are m1 and m2. Their initial velocities are u1 and u2 and final velocities are v1 and v2. Then, using conservation of momentum. m1*u1 + m2*u2 = m1*v1 + m2*v2 Both m1 and m2 are given. Their initial velocities u1 and u2 are given and one of the two final velocities v1 and v2 is given which leaves only one unknown. So substitute all those values and calculate away.
Both the gliders will be travelling at exactly the same speed as the initial velocity but in opposite directions.
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You need the initial and final velocities, and time interval to answer this question.
You need initial and final velocities (U,V) and distance (S), > acceleration = (V2 - U2) / (2 * S)
It is correct only if the object in question is subject to a constant acceleration.
change = final - initial -13 - 1 = -14 It has fallen 14 degrees.
nope butter begins to melt at 90 degrees
final minus initial denoted by lambda example: deltaT = change in temperture; final temp is 37 degrees C and initial temp is 36 degrees C, so, delta T = 37 - 36 = 1 degree C (you're getting sick?!)
You can only know the distance for sure if acceleration or deceleration is constant. Add the start and end velocities and divide by two and then multiply by the time to get your distance.