0
What happened to kinetic energy if the magnitude is being halved?
Wiki User
∙ 10y ago
Kinetic energy = 1/2 M V2 .
Double the mass . . . doubles the KE.
Cut the speed in half . . . reduces the KE to 1/4 .
Do both . . . reduces the KE to 1/2 its original value.
Wiki User
∙ 12y ago
Wiki User
∙ 12y agoLet us see with examples.
KE = 1/2(100 kg)(100 m/s)^2
= 500000 Joules
-----------------------
KE = 1/2(100 kg)(50 m/s)^2
= 125000 Joules
----------------------
500000 Joules/125000 Joules
= 4
------
The kinetic energy is reduced by a factor of 4 because the speed is squared. Try other numbers and see this as correct.
Wiki User
∙ 12y agoE = (1/2)*m*(v^2)
Let's assume v is just some constant V.
Given this our original expression is the same,
barring the capital letter:
oldE = (1/2)*m*(V^2)
For comparison, we now want to make our velo
smaller, so we'll cut it in half by multiplying by
.5:
newE = (1/2)*m*((.5V)^2))
Exponents just distribute over multiplication,
so:
newE = (1/2)*m*.25*(V^2)
Dividing oldE/newE gives us from before it's 1/4 or .25 as much.
Wiki User
∙ 12y agoBy example using constant mass.
KE = 1/2(10 kg)(20 m/s)2
= 2000 Joules
=============
500 J/2000 J * 100
= 25% reduction, or 1/4 of the energy is generated if momentum/velocity is halved.
Wiki User
∙ 10y agoYou haven't said WHAT magnitude is halved.
If it's the magnitude of velocity, then the kinetic energy is reduced 75% .
If it's the magnitude of mass, then the kinetic energy is reduced 50% .
If it's the magnitude of the cost or temperature, then the kinetic energy is unchanged.
Wiki User
∙ 14y agoHalf of its maximum value. No matter where an object is in its trajectory, the kinetic energy and the potential energy of an object will always add up to be the same.
Wiki User
∙ 12y agoKE=0.5*M*V2
So if velocity is half, KE will be one quarter.
Wiki User
∙ 9y agoWhen the pendulum bob swings by the point that marks half its maximum height, it has half its maximum KE, and its PE is halfway between its minimum and maximum values
Add your answer:
Earn +20 pts
What happened to kinetic energy is speed is halved?
The formula for kinetic energy is: KE = mv^2, in which m is mass in kilograms and v is speed in meters/second, or m/s. The unit for kinetic energy is the Joule (J), which is one kilogram·m^2/s^2. If the speed of a mass is halved, it's kinetic energy will be reduced by one quarter. For example, if a 1 kg mass has a speed of 4 m/s, its kinetic energy = 1 kg(4 m/s)^2 = 16 J. If the speed of the 1 kg mass is halved to 2 m/s, its new kinetic energy = 1 kg(2 m/s)^2 = 4 J.
What happens to speed if kinetic energy halved?
Kinetic energy is determined by mass and velocity. The velocity is halved if you double the original mass, so the kinetic energy stays the same (unless the mass added has the same kinetic energy in the observer's reference frame as the original mass).
How much do you decrease your kinetice energy when you decrease your speed by double?
Kinetic energy is given by mv2, where m is mass and v is speed. To obtain a result let me divide the new kinetic energy, m(v/2)2 (where the initial velocity is divided by two), by the initial velocity, mv2. (v2/4)/v2 = 1/4 The kinetic energy will be one fourth of what it was when the speed is halved.
What happens to the potential energy of an object if the mass is halved?
I assume you mean the gravitational potential energy. This is proportional to the mass, so if you change the mass by a factor of "a", the gravitational potential energy will change by the same factor of "a".
What happens to the speed of body when kinetic energy increase by four times?
Using; ke = (m x v^2) / 2 where ke = kenetic energy, m = mass and v = velocity, velocity has to be halved when the mass is multiplied by four in order to maintain the same kinetic energy.
What will happen to the kinetic energy of the body if the mass of the body is halved and velocity remains the same?
Kinetic energy will also be halved. Because kinetic energy is equal to 1/2 mv2
What happened to kinetic energy is speed is halved?
The formula for kinetic energy is: KE = mv^2, in which m is mass in kilograms and v is speed in meters/second, or m/s. The unit for kinetic energy is the Joule (J), which is one kilogram·m^2/s^2. If the speed of a mass is halved, it's kinetic energy will be reduced by one quarter. For example, if a 1 kg mass has a speed of 4 m/s, its kinetic energy = 1 kg(4 m/s)^2 = 16 J. If the speed of the 1 kg mass is halved to 2 m/s, its new kinetic energy = 1 kg(2 m/s)^2 = 4 J.
What happens to speed if kinetic energy halved?
Kinetic energy is determined by mass and velocity. The velocity is halved if you double the original mass, so the kinetic energy stays the same (unless the mass added has the same kinetic energy in the observer's reference frame as the original mass).
How does the kinetic energy of a body change if its momentum is halved?
Since momentum is proportional to the velocity, half the momentum means half the velocity (and therefore half the speed). And since kinetic energy is proportional to the SQUARE of the speed, half the speed means 1/4 the kinetic energy.
How much do you decrease your kinetice energy when you decrease your speed by double?
Kinetic energy is given by mv2, where m is mass and v is speed. To obtain a result let me divide the new kinetic energy, m(v/2)2 (where the initial velocity is divided by two), by the initial velocity, mv2. (v2/4)/v2 = 1/4 The kinetic energy will be one fourth of what it was when the speed is halved.
What happens to the potential energy of an object if the mass is halved?
I assume you mean the gravitational potential energy. This is proportional to the mass, so if you change the mass by a factor of "a", the gravitational potential energy will change by the same factor of "a".
How does the gravitional force change if theier mass are halved?
If the masses of two objects are each halved, and the distance between them doesn't change, then the mutual gravitational forces of attraction between them are reduced to 1/4 of their original magnitude.
What happens to the speed of body when kinetic energy increase by four times?
Using; ke = (m x v^2) / 2 where ke = kenetic energy, m = mass and v = velocity, velocity has to be halved when the mass is multiplied by four in order to maintain the same kinetic energy.
What will happen to the potential energy of a body when its height is kept the same if the mass of the body is halved?
according to the equation for potential energy of a body i.e.''mgh'' if mass of the body is halved m/2 keeping it hight same then its energy will become half as well...
How many joules of kinetic energy does a 750 kg car traveling at 65 mi hr have. By what factor would its kinetic energy decreases if the car travel half as fast?
For this question, we will use the formula K = 1\2 mv2. But first, we must convert the 65 miles per hour into meters per second. Multiply miles per hour by a factor of 1.609 to get kilometers per hour. Divide this answer by 3600 to get kilometers per second. Multiply this by 1000 to get meters per second. In this case, the velocity in meters per second is aproxamitely 29 meters per second. To get the kinetic energy, we multiply one half, times the mass 750 kg, times 292 meters per second. This yields 315375 Joules. If we halved the velocity, the kinetic energy would be one-fourth that of the original kinetic energy. This is because the velocity is squared. This holds true if we go to one third the original speed. Then it would be one-ninth of the original kinetic energy.
What is 8000 halved and halved again?
2,000
What happens to the energy carried in a given time interval by a mechanical wave when the waves amplitude is halved?
the energy is reduced by a factor of 4. It is reduced by (1/4)
