Yes. That's a step you should usually include, to avoid the result from looking more accurate than it actually is.
Yes.
16.506
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
To find a number to two significant figures or any amount of significant figures you look at one plus the amount of asked figures, in this case the third significant figure, and if it is 5 or greater increase the asked amount of significant figures by one. If it is 4 or less make no changes to your number. Finally report the calculated number with the asked amount of significant figures.
0.0714
0
16.506
The accuracy of the answer is limited to the LEAST significant figures of the input. So if two measured quantities are multiplied or divided, one of which is accurate to only two significant figures, and other to six significant figures, the answer is only accurate to two significant figures. HOWEVER: use all the figures you have for the calculation, and then round your answer to two significant figures. Also, however, remember that if you are multiplying by an actual exact number, as in doubling, the significant figures of that 2 is unlimited, so the answer is only limited by the significant figures of the number you are doubling.
4.107
32.2
3.134
The least number of significant figures in any number of the problem determines the number of significant figures in the answer.
0.06
6.9554
130.457 = 130 to 3 significant figures
To find a number to two significant figures or any amount of significant figures you look at one plus the amount of asked figures, in this case the third significant figure, and if it is 5 or greater increase the asked amount of significant figures by one. If it is 4 or less make no changes to your number. Finally report the calculated number with the asked amount of significant figures.
Significant figures are calculated using various rules.ÊAll non-zero numbers are significant and all zeros that are to the right of the decimal point as well as at the end of a number are significant.ÊTherefore, 1.050L has 4 significant figures.
8.235