As the distance from a charged particle increases the strength of its electric field DECREASES.
It will decrease as well.
The magnitude of the electric potential is dependent upon the particle's charge and the electric field strength.
I am not sure but i thinks they are:Positive chargeNegative charge
To increase the strength of a magnet you need to stack it between two stronger magnets or electromagnets. To weaken it, you'd have to heat it up, or use the same method as when strengthening, only this time you should flip the magnet so it would repel the stronger (electro)magnets.
The strength of the gravitation force between two objects depends upon the distance between the two objects and their masses. F = (M1*M2*G)/R2 (Newton's Law of Gravitation) Here M1 and M2 are the masses of the two objects, G is the universal gravitational constant, and R is the distance between the two objects. If the masses of the two objects are large the attraction between them will also be large. However, as the radius increases the gravitational force between the two decreases by the square of the distance. So, the gravitational force depends mainly upon the distance between the two objects, but also significantly upon the masses of the two objects.
Generally, increased moisture levels will lower breakdown strength, especially if the dielectric readily absorbs water. Increasing temperature generally decreases breakdown strength of solid dielectrics. The dielectric strength of some materials may increase with temperature within limited temperature ranges. However, dielectric strength eventually begins to decrease at higher temperatures.
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Statement itself is incomplete. How can one say whether it is true or false>
No. The electric force in this case decreases.
An electric field gets stronger the closer you get to a charge exerting that field. Distance and field strength are inversely proportional. When distance is increased, field strength decreases. The opposite is true as well. Additionally, field strength varies as the inverse square of the distance between the charge and the observer. Double the distance and you will find that there is 1/22 or 1/4th the electric field strength as there was at the start of your experiment.
The strength of the electric field approaches zero
I really doubt it. If it were, then the strength of the electric field from a charged particle on the far side of the Andromeda Galaxy would be totally unbearable, and it would be completely impossible to stick a charged balloon to the wall in my house.
No, the strength of the electric field decreases with distance from a charged object. The electric field follows an inverse-square law, meaning it decreases with the square of the distance from the source charge. So, the closer you are to the charged object, the stronger the electric field.
The magnitude of the electric potential is dependent upon the particle's charge and the electric field strength.
The magnitude of the electric potential is dependent upon the particle's charge and the electric field strength.
Force is inversely related to the square of the distance. Hence as the distance increases the force decreases.
Force is inversely related to the square of the distance. Hence as the distance increases the force decreases.
The strength of an electric field depends on the charge that causes it, and on the distance from the charge.