12 and 13.
Divide the larger number by the smaller. If the result has no remainder (no decimal) then the smaller number is a factor of the larger.
First of all you need serious help with your grammar, more than your math. I will try to make sense of what you wrote. 24 and 4 are the numbers you are looking for.
The sum of two even numbers is always an even number. The sum of two odd numbers is always an even number.The sum of an even number and an odd number is always an odd number.Because integers alternate between even and odd, adding two consecutive integers will always result the sum of an odd number and an even number, which, as stated above, will always be an odd number.Another way to look at it:An even number is divisible by 2, therefore, 2*n (where n is an integer) is always an even number.2*n+1 would be the next number after 2*n (so 2*n & 2*n+1 are consecutive integers).If we add these numbers together, we get 4*n+1 = 2(2*n)+1. Since 2(2*n) is an even number, adding 1 makes it an odd number._________________________________________________________________________I'm not going to but in or anything, seriously that was a good answer
It's a positive number. Here's the rule: In multiplication and division . . . -- If both numbers have the same sign, then the result of multiplying or dividing them is positive. -- If the two numbers have different signs, then the result of multiplying or dividing them is negative.
Let's called the first integer x. The second would be x+1 and the third x+2. Adding all these integers together would result in 114:x+(x+1)+(x+2)=114x+x+1+x+2=1143x+3=114Subtract 3 from both sides:3x=111Divide both sides by 3:x=37The first number is 37, so the three numbers are 37, 38, and 39.
The integers are 10 and 11.
They are 5 and 6 because 5+(2*6) = 17
Let the smaller be n, then the larger is n+1; and: n + 4(n+1) = 59 → n + 4n + 4 = 59 → 5n = 55 → n = 11 → the two consecutive integers are 11 and 12.
6x + 5 = 53 6x = 48 x = 8 8 + 45 = 53 8 and 9
55 and 57
12 and 13.
x+5(x+1)=53 6x+5=53 6x=48 x=8 numbers=8 and 9
There is not such set of integers.
Suppose the smaller integer is x, then the larger one is x+1. x + 3*(x+1) = 43 That is x + 3x + 3 = 43 so that 4x = 40 and that implies that x = 10 and so the other integer is 11.
Let the integers be n and n + 1.n + 3(n+ 1) = 47 4n + 3 = 47 4n = 44 n = 11 n+ 1 = 12.
this is a algebraic word problem: we know we have two consecutive integers so x + 1 = y and we know that the smaller one (x) added to three times the larger, the results is 23 so x + 3y = 23 substitute (x+1) for y: x + 3(x+1) = 23 4x + 3 = 23 4x = 20 x = 5 y = 6
Integers are whole numbers therefore it follows that two consecutive integers can't result into a decimal number