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Zero.
The velocities of the two bodies after the elastic collisions are given by V1=(M1-M2)U1/(M1+M2)+2M2U2/(M1+M2) V2=(M2-M1)U2/(M1+M2)+2U1M1/(M1+M2) Where, V1,V2 are the velocities of the two bodies after collision. U1,U2 are the velocities of the two bodies before colision.(U1>U2) M1,M2 are the masses of the two bodies. when the mass of two bodies are equal that is M1= M2 then V1=0+2MU2/2M=U2 V2=0+2MU1/2M=U1 Thus when two billiard balls of equal masses undergo perfectly elastic collision the velocities the two bodies are interchanged after the collision.
The case you're describing is called an inelastic collision. Two objects collide, stick to each other and continue their motion as one body. Due to momentum conservation principle, sum of two bodies momenta before collision has to be equal to momentum of the one body after collision. pbefore = pfirst + psecond = m1v1 + m2v2 pafter = (m1 + m2)vcommon Since pbefore = pafter, (m1 + m2)vcommon = m1v1 + m2v2 We can get vcommon from that: vcommon = (m1v1 + m2v2) / (m1 + m2) [vi are velocities of bodies before collision and vcommon is a velocity after collision]
The idea is to use conservation of momentum. Calculate the total momentum before the collission, add it up, then calculate the combined velocity after the collision, based on the momentum.
True.
Stellar Collision Theory: The coming together of two astronomical bodies (stars), which through the force of gravity, merge into one larger unit
The law of conservation of momentum useful in analyzing the collision between two bodies because there is use to be the collision between the two bodies reason for that is law of conservation of momentum is that the total sum of momentum is equal means constant after the total sum of momentum of two bodies. so if you don't be the collision between two bodies you will not aware of the meaning of momentum.
In an inelastic collision kinetic energy is lost (generally through energy used to change an objects shape), but the two objects rebound off each other with the remaining kinetic energy. In a perfectly inelastic collision the two objects stick together after the collision.
Zero.
The velocities of the two bodies after the elastic collisions are given by V1=(M1-M2)U1/(M1+M2)+2M2U2/(M1+M2) V2=(M2-M1)U2/(M1+M2)+2U1M1/(M1+M2) Where, V1,V2 are the velocities of the two bodies after collision. U1,U2 are the velocities of the two bodies before colision.(U1>U2) M1,M2 are the masses of the two bodies. when the mass of two bodies are equal that is M1= M2 then V1=0+2MU2/2M=U2 V2=0+2MU1/2M=U1 Thus when two billiard balls of equal masses undergo perfectly elastic collision the velocities the two bodies are interchanged after the collision.
The case you're describing is called an inelastic collision. Two objects collide, stick to each other and continue their motion as one body. Due to momentum conservation principle, sum of two bodies momenta before collision has to be equal to momentum of the one body after collision. pbefore = pfirst + psecond = m1v1 + m2v2 pafter = (m1 + m2)vcommon Since pbefore = pafter, (m1 + m2)vcommon = m1v1 + m2v2 We can get vcommon from that: vcommon = (m1v1 + m2v2) / (m1 + m2) [vi are velocities of bodies before collision and vcommon is a velocity after collision]
collision is when two plates collide conservative is when two plates rub together
they both crash
a cosmic colision is when two or more bodies in space colide
1. Indo-Australian and Eurasian. This types is called Collision. 2.South American and Pacific. This is called Destructive.
The collision is elastic because energy will be conserved. The materials don't react with each other (Velcro does not stick to magnets and magnets do not stick/repel velcro) so its no different than two balls hitting each other. If it was velcro to velcro, and the carts stuck together at the collision, this would be considered an inelastic collision because a lot of Kinetic Energy would be lost. Regardless of the collision, momentum is always conserved.