There is an infinite set of numbers that fulfills this condition - all numbers of type 5n + 4, for an integer "n", for example, 4, 9, 14, 19, -1, -6, etc.
No.
26. This is because when you divide 26 by 5, you have a remainder of 1, and when you divide it by 4, you have a remainder of 2
58
20 / 4 = 5 (no remainder) 21 / 4 = 5 remainder 1 22 / 4 = 5 remainder 2 23 / 4 = 5 remainder 3 24 / 4 = 6 (no remainder) Therefore the numbers that can remain after you've divided a number by four are 0, 1, 2, and 3.
4
No.
24
26. This is because when you divide 26 by 5, you have a remainder of 1, and when you divide it by 4, you have a remainder of 2
58
this does not make sense. What number?
The number left when you divide (ex.) ___ 5)21 4 remainder 1
5 will go into 9 once with a remainder of 4.
it is 24, 24 divide by five is 4 with a remainder of four. 24 divided by 5= 4 =20 +4= 24
Your question's meaning eludes me. You can divide any number by 5, whether or not it is a remainder, and why would you want to divide a remainder by 5 anyway?
assume dividing into whole number if you divide by 4 then remainder will be 0,1,2, or 3 by 6 then remainder will be 0,1,2,3,4 or 5 by 9 then remainder will be 0,1,2,3,4,5,6,7 or 8
Any number of the form 5n+4 where n is an integer.
When you divide by 5, the remainder can be 0, 1, 2, 3, or 4, but no more than 4.