the number is 43:
43:7=6 remainder 1
43:9=4 remainder 7
43:11=3 remainder 10
Also possible: 241, 439, 637, 835, 1033, 1231, 1429, 1627, 1825, 2023, 2221, 2419, 2617, 2815, 3013, 3211, 3013, 3211, 3409, 3607... where number is 198xN+43 and N is positive integer number
If you take any four consecutive numbers and divide them by 3, the remainders are as follows: 9/3 = 3 10/3 = 3 remainder 1 11/3 = 3 remainder 2 12/3 = 4 Therefore, the highest remainder you can have by dividing a whole number is 2.
1
You repetitively divide the number by two, taking the remainder as the digit (in binary). When you divide by 2, the remainder will either be 0 or 1.Example: convert 23 (base 10) to binary:23/2 = 11, remainder 1 (this is the ones digit)11/2 = 5, remainder 1 (this is the twos digit)5/2 = 2, remainder 1, (this is the fours digit)2/1 = 1, remainder 0, (this is the eights digit)1/2 = 0, remainder 1, (this is the sixteens digit). So now combine the digits (sixteens is the highest digit in this number):23 (base 10) = 10111 (base 2)
16.2727
11
9000000
Eleven.
If you take any four consecutive numbers and divide them by 3, the remainders are as follows: 9/3 = 3 10/3 = 3 remainder 1 11/3 = 3 remainder 2 12/3 = 4 Therefore, the highest remainder you can have by dividing a whole number is 2.
Yes- A remainder can be any number less than the dividend (the number by which the divisor is divided). An example of a 2 digit number is: 131/11=11 remainder 10.
If your improper fraction does not produce a remainder when you divide it, then it's just a whole number. 22/11 = 2
You use multiplication. Example: Problem is- 11 divided by 2. You would take the 2 and times it by 5, (2x5=10) with a remainder of 1 to equal 11. The answer is 5 with a remainder of 1. Mathematics is a great subject, there are so many ways of calculating and deriving answers and generate the same answer. Here's another way of doing it, 11 divided by 2 11 is not divisible by 2 but 10 is , there are 5 2's in 10 and that remains 1 as your remainder therefore, 11 / 2 = 5 remainder 1 tip: if you are dividing a number , look for the nearest multiple of the number and then the remaining is your remainder. You can have an answer as well with a decimal and that would be another lesson. hope this helps
Yes, you can have a remainder of 5 when you divide by 6. If you divide 11 by 6, it will go into it one time with a remainder of 5.
Because 22 is the smallest number that both 2 and 11 divide into evenly with no remainder.
Because 33 is the smallest number that both 3 and 11 divide into evenly with no remainder.
The largest [integer] remainder is 10. If the remainder was any more you would get one (or more) lots of 11.
Divide the numerator by the denominator, using integer division. The result is the integer; put the remainder over the denominator. Thus, 11/10 = 1 1/10.
Divide each of these numbers by 11, and the remainder is 5.