There are 8 different combinations.
There are 145 permutations that total 14.
Not asked, but answered for completeness sake; there are 1296 possible permutations of four dice, making the probability of a sum of 14 being 145 in 1296 or about 0.1119.
17,576 possible combinations * * * * * Not quite! This is the total number of permutations of 3 letters out of 26. AAB is counted as being different from ABA or BAA. But these are the same combinations. Thus there are 26 combinations of just one letter. 26*25 combinations of two letters and 26*25*24/(3*2*1) of three. In all, that makes 26 + 650 + 2600 = 3276
Simple enough to solve. The answer is a power of two. Assuming you have two possible digits, say for example, 3 and 4, then you simply have to multiply it by how many numbers you want to get the total number of combinations. Each number can be 3 or 4 in this case, and you have 5 numbers. That's two to the fifth. Five combinations of any two numbers. 2x2x2x2x2. The answer is 32 combinations.
10 * * * * * That is just plain wrong! It depends on how many numbers in each combination but there are 1 combination of 4 numbers out of 4, 4 combinations of 3 numbers out of 4, 6 combinations of 2 numbers out of 4, 4 combinations of 1 number out of 4. A grand total of 15 (= 24-1) combinations.
Consider one placement at a time. The first book on the shelf could be any of seven. The second could be any of the remaining six. This continues with the rest. The total combinations are: 7! = 7*6*5*4*3*2*1 = 5040
There are 69 total possibilities. Imagine having nine boxes, that each hold how many possibilities each individual dice can hold. Any two of the dice can only be a six, therefore any two of the boxes can only have a 1 (only one possibility). The rest of the boxes can be anything, other than 6 (so the rest of the boxes have 5 possibilities each). [1] [1] [5] [5] [5] [5] [5] [5] [5] Now multiply all the possibilities together you get total number of combinations. In this case, it's 57. You can use this same strategy to see why the total number of possibilities is 69. The answer is total restricted combinations divided by total combinations. 57 / 69 ~= 0.007752 (or roughly 0.78%)
64
When trying to work out how many different combinations there are, you need to know how many options there are for each value. If the password only contains lower case letters, then we have 26 options for each value. For each letter in the password, there are 26 options, so the total number of possible options is 26x26x26x26x26x26 or 266 This equals 308,915,776 so there are 308,915,776 possible different combinations of six letters.
In the short form, the total number of different combinations you can get are 64. The work to obtain that number is shown below.Let's call each of them different names. There will be starter 1, 2, 3, 4, and 5.The possible combinations are as follows for the first set of numbers:# 1,2,3,4,5 # 1,2,3,5,4 # 1,2,4,5,3 # 1,2,4,3,5 # 1,3,2,4,5 # 1,3,2,5,4 # 1,3,4,2,5 # 1,3,4,5,2 # 1,4,2,3,5 # 1,4,2,5,3 # 1,4,3,2,5 # 1,4,3,5,2 # 1,5,2,3,4 # 1,5,2,4,3 # 1,5,3,4,2 # 1,5,3,2,4 Those are the possible combinations if the starter 1 went first. Multiply the total combinations for the first set by 4, and you get a total of 64 combinations.
2 to the 7th power = 128 * * * * * No. That is the total number of combinations, consisting of any number of elements. The number of 2 number combinations is 7*6/2 = 21
Two, heads or tails.
6^4 = 1296 combinations but some are repeatable e.g. 1221 = 2121 = 2112 etc. so for the total number of non repeatable combinations with 4 dice, use pascals triangle to get 126 unique combinations.
A lot
Right around 32.8 Billion
454
If no digit can be repeated then there are 5 combinations, abcd, abce, abde, acde and bcde. If you regard abdc as different from abcd then each of the 5 basic sets could be arranged 24 ways and the total would be 120 combinations.
There are 210 different combinations using 6 players out of 10 available to make a team. With 6 different captain options per combination, the total number of combinations would be 1,260.
15/21= 71.43% chance. It's the number of possible throws without repetition divided by the total different combinations of dice throw. Here is a handy Combination and Permutation Calculator: http://www.mathsisfun.com/combinatorics/combinations-permutations-calculator.html