Math and Arithmetic

Statistics

Probability

567

No, not if it is a fair coin.

The probability that the coin will land on heads each time is 1/2. (1/2) to the tenth power is 1/1024. This is the probability that the coin will not land on heads. Subtract it from one to get the probability that it will : 1-(1/1024)There is a 1023/1024 or about 99.90234% chance that the coin will land on heads at least once.(There is a 1/1024 chance that the coin will land on heads all four times.)

The probability that a coin will land on heads - at least once - in six tosses is 0.9844

Since it is a fair coin, the probability is 0.5

Since it is a certainty that a coin must land on either heads or tails, the probability must be 1.

50/50. There are two sides (heads and tails), so half of the time it will land on heads. 49.5% or something like that because the coin can land on heads, tails, or on its edge. but the likelihood is like a fraction of a percent, but it is possible

the probability is actually not quite even. It would actually land heads 495 out of 1000 times because the heads side is slightly heavier

This is a probability question. Probabilities are calculated with this simple equation: Chances of Success / [Chances of Success + Chances of Failure (or Total Chances)] If I flip a coin, there is one chance that it will land on heads and one chance it will land on tails. If success = landing on heads, then: Chances of Success = 1 Chances of Failure = 1 Total Chances = 2 Thus the probability that a coin will land on heads on one flip is 1/2 = .5 = 50 percent. (Note that probability can never be higher than 100 percent. If you get greater than 100 you did the problem incorrectly) Your question is unclear whether you mean the probability that a coin will land on head on any of 8 flips or all of 8 flips. To calculate either you could write out all the possible outcomes of the flips (for example: heads-heads-tails-tails-heads-tails-heads-heads) but that would take forvever. Luckily, because the outcome of one coin flip does not affect the next flip you can calculate the total probability my multiplying the probabilities of each individual outcome. For example: Probability That All 8 Flips Are Heads = Prob. Flip 1 is Heads * Prob. Flip 2 is Heads * Prob. Flip 3 is Heads...and so on Since we know that the probability of getting heads on any one flips is .5: Probability That All 8 Flips Are Heads = .5 * .5 * .5 * .5 * .5 * .5 * .5 * .5 (or .58) Probability That All 8 Flips Are Heads = .00391 or .391 percent. The probability that you will flip a heads on any of flips is similar, but instead of thinking about what is the possiblity of success, it is easier to approach it in another way. The is only one case where you will not a heads on any coin toss. That is if every outcome was tails. The probability of that occurring is the same as the probability of getting a heads on every toss because the probability of getting a heads or tails on any one toss is 50 percent. (If this does not make sense redo the problem above with tails instead of heads and see if your answer changes.) However this is the probability of FAILURE not success. This is where another probability formula comes into play: Probability of Success + Probability of Failure = 1 We know the probability of failure in this case is .00391 so: Probability of Success + .00391 = 1 Probability of Success = .9961 or 99.61 percent. Therefore, the probability of flipping a heads at least once during 8 coin flips is 99.61 percent. The probability of flipping a heads every time during 8 coin flips is .391 percent.

The probability of a coin landing on heads is 0.5. It does not matter which toss it is, and it does not matter what the toss history was.

About a 1 in 16 chance of getting a coin to land on heads 4 times in a row.

There is a 50% chance that it will land on heads each toss. You need to clarify the question: do you mean what is the probability that it will land on heads at least once, exactly once, all five times?

The probability of a fair coin to land head is 1/2. Since for 4 flips it must land heads each time, the probability of 4 heads is 1/2 * 1/2 * 1/2 * 1/2 = 1/16.

The probability that a coin flipped four consecutive times will always land on heads is 1 in 16. Since the events are sequentially unrelated, take the probability of heads in 1 try, 0.5, and raise that to the power of 4... 1 in 24 = 1 in 16

There are two sides on a coin. The odds are 50:100, or 1:2. Half the time the coin SHOULD land on heads.

50% probablility, or 1/2, that is, a one in two chance.There is an equal chance that the coin will land either heads or tails.

you would think there is a 50% chnce of it landing on heads. However due to the weight of the metal on the picture on the coin it is actually about 5009/10,000 chance it will land on heads.

Zero. Since coins land on Heads or Tails and not numbers.

because there are only 2 sides. It can land on one of those 2 sides.

No. There are 2 sides of the coin, so it's a 50 50 chance. There is an equal oppurtunity for it to land on heads or tails.

ignoring the minute chance that it will land on it's side as well as assuming that the air resistance due to the different patterns in the coin is negligible the chance of a coin landing heads is 50%

There is a 1/6 chance of rolling a 4 on a fair die, and a 1/2 chance of a fair coin landing heads up. Multiply 1/6 X 1/2. The probability of both happening is 1/12.

The probability of getting heads on three tosses of a coin is 0.125. Each head has a probability of 0.5. Since the events are sequentially unrelated, simply raise 0.5 to the power of the number of tosses (3) and get 0.125, or 1 in 8.

The probability that exactly one will land heads up is 0.15625

The probability of the first coin landing heads is half (or 1/2). Similarly, the probability of the second and third coins landing heads are also 1/2 in each case. Therefore, the probability of having three heads is: (1/2)(1/2)(1/2) = (1/8)

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