FS= critical hydraulic gradient/exist hydraulic gradient icr=(saturated unit wt - water unit wt)/water unit wt
take 1 g of casava flour in a centrifuge tube and add 10 ml od water in it heat it at 60, 80, 100 oC, centrifuge it and decant the supernant. weigh the residue. swelling power= wt. of residue / wt. of flour (g/g)
"wt"?
wt is an abbreviation for weight
The maximum solubility of n-isopropylacrylamide in water is approximately 45-48 wt%.
Take the wt and cube it.
details about PUC like whyit is /@ wt frequency/govt standards etc. diff vehicles cat.?
Where do you find the external input channel on the tretech television remote?
mm is millimeters & wt is weight
i don't want pregnancy wt will do
acre is related to land as gallons are related to water
To solve this problem, we basically have 2 equations and 2 unknowns. The unknowns are the (volume of water) & the (volume of 70 wt%) nitric acid to add. * This problem will assume that you are interested in making 1 L (or 1000 mL) of 5 wt% nitric acid solution. Equation 1: (volume of water) + (volume of 70 wt% nitric acid) = 1000 mL Equation 2: mass of nitric acid / [mass of water + mass of 70 wt% nitric acid solution] = 0.05 (0.05 is 5 wt%) * Remember that mass = density * volume * Remember that 70 wt% nitric acid solution mean that for 100 grams (gm) of this acid, then there's 70 grams of HNO3 * Remember that density of 70 wt% nitric acid solution is 1.413 gm/cm^3 * Remember that density of water is 1 gm/cm^3 Equation 2 is now re-written as: [(density of 70 wt% nitric acid soln)*(volume of 70 wt% nitric acid)*0.70] / [(volume water)*(1gm*cm^3) + (volume of 70 wt% nitric acid)*(1.413gm/cm^3)] = 0.05 Solving for the 2 equations gives answer to the 2 unknowns: Answer: To make 1000 mL of 5 wt% nitric acid solution, add 1) 51.63 mL of 70 wt% nitric acid solution 2) 948.37 mL of water