The earth is not a perfect sphere. The spin of the earth causes it to buldge out at the equator, which means the equator is further from the center of the earth then the poles are. The further an object is from the center of mass of another object, the less effect the gravity of those objects will have on each other. So at the equator, an object is being effected less by the gravity of the earth then it is at the poles.
because the force of gravity is weaker at the equator than at the poles.
The closer an object gets to the center of the earth, the greater the pull of gravity on that object.
The weight of an object is slightly less at the equator than at the poles because of the earth's tilt on its axis.
Mass. . . . . same at the poles as it is at the equator. Weight . . . more at the poles Cost . . . . . more at the poles
say mass(m) = 100 kgvelocity(v) at equator = 464.6 metres / secondradius(r) to earth surface = 6 371 000 metresacceleration due to gravity (g) = 9.82 (m / s) / s.the force of attraction (f) anywhere on earths surface, = m * g = 100 * 9.82 = 982 newtons.the force of repulsion / centripetal force (f) at the equator = mass * (v^2) / r =3.39 newtons
Gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles. This means an object will weigh about 0.5% more at the poles than at the Equator.
The closer an object gets to the center of the earth, the greater the pull of gravity on that object.
The weight of an object is slightly less at the equator than at the poles because of the earth's tilt on its axis.
Because of centripetal acceleration you will weigh a tiny amount less at the equator than at the poles.
much less
less gravity pull farther away from central pole
Due to the centrifugal force caused by Earth's rotation opposing gravity for objects on the equator, objects there weigh about 0.5% less than they do on the poles. So an object that weighs 200 N at the poles weighs about 199 N on the equator.
Mass. . . . . same at the poles as it is at the equator. Weight . . . more at the poles Cost . . . . . more at the poles
say mass(m) = 100 kgvelocity(v) at equator = 464.6 metres / secondradius(r) to earth surface = 6 371 000 metresacceleration due to gravity (g) = 9.82 (m / s) / s.the force of attraction (f) anywhere on earths surface, = m * g = 100 * 9.82 = 982 newtons.the force of repulsion / centripetal force (f) at the equator = mass * (v^2) / r =3.39 newtons
Rotation.
Gravity increases from about 9.780 m/s2 at the Equator to about 9.832 m/s2 at the poles. This means an object will weigh about 0.5% more at the poles than at the Equator.
Well the above question is not true, The same object will weigh less at the equator than at the poles (of Earth). The force is the force of gravity and the effect is because the object placed at the poles will be nearer the center of the Earth than at the equator because the Earth is an Oblate Spheroid.
gravity
The closer an object gets to the center of the earth, the greater the pull of gravity on that object.