Iodine
Iodine chloride is polar, since chlorine has a higher electronegativity than iodine has.
Yes with any element with a higher electronegativity. Carbon has an electronegativity of 2.55 on the Pauling scale. Checkout the table in wikipedia in the article "electronegativity", you can see that nitrogen, oxygen , sulfur, and fluorine, chlorine, bromine, iodine all have higher electronegativities.
The electronegativity of an element is important in figuring out how polar a molecule will be. The higher the electronegativity of an element is compared to another, the more polar the molecule will be. For example, a bond between Flourine and Hydrogen will be very polar, because Flourine has a very high electronegativity, and hydrogen has a very low electronegativity.
There are two elements. They are Fluorine and Oxygen
As you can see on the periodic table.. Carbon is number 6. And Iodine is 53. Carbon, loves it's electrons more than Iodine. So it is said that Carbon has a higher electronegativity, and wants to keep it's electrons as long as possible. (Electron config: 2,4) Iodine, loves it's electrons less than Carbon. As it's has many more electron shells and electrons it has a lower electronegativity. When Iodine is heated, it has a a lower melting point than Carbon because of this electronegativity (it doesn't really want it's electrons) and so the bonds breaks, quicker than what the bonds of the Carbon atom do. Hope this helps.
Iodine chloride is polar, since chlorine has a higher electronegativity than iodine has.
Yes with any element with a higher electronegativity. Carbon has an electronegativity of 2.55 on the Pauling scale. Checkout the table in wikipedia in the article "electronegativity", you can see that nitrogen, oxygen , sulfur, and fluorine, chlorine, bromine, iodine all have higher electronegativities.
The electronegativity of an element is important in figuring out how polar a molecule will be. The higher the electronegativity of an element is compared to another, the more polar the molecule will be. For example, a bond between Flourine and Hydrogen will be very polar, because Flourine has a very high electronegativity, and hydrogen has a very low electronegativity.
There are two elements. They are Fluorine and Oxygen
A fluorine atom has a higher electronegativity than an atom of any other element.
This rare metal has the lowest electronegativity on the periodic table. With an electronegativity number of 0.7 this element donates it's electron very easily to the higher electronegative nonmetals.
The electronegativity of chlorine is higher than gold.
As you can see on the periodic table.. Carbon is number 6. And Iodine is 53. Carbon, loves it's electrons more than Iodine. So it is said that Carbon has a higher electronegativity, and wants to keep it's electrons as long as possible. (Electron config: 2,4) Iodine, loves it's electrons less than Carbon. As it's has many more electron shells and electrons it has a lower electronegativity. When Iodine is heated, it has a a lower melting point than Carbon because of this electronegativity (it doesn't really want it's electrons) and so the bonds breaks, quicker than what the bonds of the Carbon atom do. Hope this helps.
No, the bond electrons are weighted towards the element with the higher electronegativity, while forming the ionic bond.
Electronegative charge increases across the periodic table to the right and up into the corner ( excepting the Nobel gasses ), so the two elements that would have higher electronegativity in that direction and in order. Oxygen and fluorine.
Rubidium; the next higher atomic numbered element in the same column of the periodic table always has a higher atomic radius, with some exceptions among transition elements due to the "lanthanide contraction". However, potassium and rubidium are not transition elements.
No, the bond electrons are weighted towards the element with the higher electronegativity, while forming the ionic bond.