y = 0x + 3 or just
y = 3
y = 3
If you mean a slope of 2 and a point of (1, 4) then the equation is y = 2x+2
Y+2 = 2 (x-3)
y = 1/3x+4/3
If you mean a slope of -10 through the point (1, 4) then the equation is y = -10x+14
If you mean a slope of -12 through the point (5, 3) the equation is y = -12x+63
y = 2x + 1.
-40
If you mean a slope of 2 and a point of (1, 4) then the equation is y = 2x+2
It represents: y = x-35 or as x-y-35 = 0
It represents: y = x-35 or as x-y-35 = 0
Y+2 = 2 (x-3)
General formula
The equation of the line is of the form y = 3x + c where c is a constant. The point (4,9) is on the line, so substituting x=4, y=9 in the equation, 9 = 3*4 + c = 12 + c so c = -3 So the equation of the line is y = 3x - 3
2
y=mx+b y0=mx0+b 5=3*2+b b=5-5=0 y=3x+0
y = 1/3x+4/3
A derivative of a function represents that equation's slope at any given point on its graph.