Top Answer

A temperature change by one degree on Celsius scale equals temperature change of 1.8 degree on Fahrenheit scale

or F (Fahrenheit) = 1.8 C (Celsius) + 32

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098 deg F = 36.66... deg C.

# include<stdio.h> main() { int a,b,c; print f("enter the values of a,b,c"); scan f("%d%d%d",&a,&b,&c); if((a>b)&&(a>c)) print f("Greatest value is a =%d",a); else if((b>a)&&(b>c)) print f("Greatest value is b=%d",b); else print f("Greatest value is c=%d",c); }

C is for cost (value before shipping) and F is for freight/shipping.

Subtract 32 from the Fahrenheit value, then divide by 1.8. Thus 86 F, subtract 32 to get 54, divide by 1.8 to get 30 C. 32 F = 0 C (freezing point of water). So if below freezing you will get a negative number for the C value. 0 F = -17.8 C. If you are below 0 F, then you have to add the negative F value to -32 before dividing by 1.8, the result is a negative C value. Thus for -20 F, add to -32 to get -52, divide by 1.8 to get - 28.9 C. The scales coincide at -40, that is -40 F = -40 C, as you should be able to verify now.

The temperature is about 11.4 °F which is about the same as -11.4 °C.(11°F = - 11.67°C)You can solve by using the conversion formula°F = (9/5 °C) +32 and set °F to (-C)-C = 1.8 C + 32-C - 1.8 C = 32-2.8 C = 32C = -11.4 then F = -C and F ~ 11.4The actual value is exactly 11 3/7 degrees F (equals -11 3/7 degrees C)(9/5 x 80/7) - 32 = (720 - 1120)/35 = - 400/35 = - 80/7

c# d# f# g# a# g# f# f# f# f# f# d# c# d# f# g# a# g# f# f# f# f# f# d# f f f f f f f d# c# c# c# d# d# d# c# f f f f f f f d# c# c# c# d# d# d# c# a# a# c# d# a# a# c# d# f f f f f f f d# c# c# c# d# d# d# c# f f f f f f f d# c# c# c# d# d# d# c#

C-C-F C-F-A C-F-A-C-F-A-C-F-A F-A-C A-F-C C-C-F

23.8°C = 74.8°F23.8°C multiplied by 1.8 +32 = 74.8°F

The formula, for any value is C = 5/9*(F - 32). Let F = -40 and solve for C.

C, E, G, E, C, E, G, E, A, C, E, C, A, C, E, C, F, A, C, A, F, A, C, A, F, F, F, F, F, F, F, F, F, F. C, E, G, E, C, E, G, E, A, C, E, C, A, C, E, C, F, A, C, A, F, A, C, A, F----, F. Hope it helps :)

If for the two integers a + b = c, a is larger than zero and b is larger than the absolute value of the first number, then c is always positive. If a is smaller than zero, and b is larger than the absolute value of the second number, then c is positive. If a is smaller than zero, and b is smaller than the absolute value of the second number, then c is negative.

F= 9/5*c+32 =0 + 32 = 32°f.

This is the whole of one verse. F F F C D D C A A G G F C F F F C D D C A A G G F C C F F F C C F F F F F F F F F F F F F F F F F F C D D C A A G G F

Let f be differentiable on [a,b] and suppose that k is a number between f'(a) and f'(b). Then there exists a point c ε (a,b) such that f'(c)=k.

C, E, G, E, C, E, G, E, A, C, E, C, A, C, E, C, F, A, C, A, F, A, C, A, F, F, F, F, F, F, F, F, F, F. C, E, G, E, C, E, G, E, A, C, E, C, A, C, E, C, F, A, C, A, F, A, C, A----, A. :) Hope this helps :)

c,c,f,f,f,f,c,f,f,f,f,f,c,f,f,e,d,c,c,c,e,e,e,e,e,e,e,e,e,e,e,d,c,c,d,e,f,c,c,f,f,c,c,c,f,f,f,c,c,c,f,f,e,d,c,c,c,e,e,e,e,e,e,e,d,c,c,d,e,f

C g g f g f c c d d c d f g a g f c c g f d c g g f g f c d d c d f g c c a g f c a g d f a g f c a g f g c f e d c e d c d f a g f d d f a g c d f f a g f d f g c g g f g f c c d d c d f g a g f c a g f d c g g f g f c d d c d f g c c a g f c a g d f a g f c a g f g c f e d c e d c d f a g f d d f a g c d f f a g f d f g c g f g f g f c c d f c d f c g g-f g-f g-a-f c d f c d f c g g-f g-f g-f-d c d f c d f c g g-f g-f g-a-f

T| Capitals on the notes signify sharps (the black keys) A| B| Also see my Alicia Keys tab of the Empire State of Mind 2 for the chords! N| PEACE! A| ~Steph~ B| B| E| R5|F-F-F----- R| R4|F-F-F----- .| L3|F-F-F-F--- C| L3|----C----- O| L2|b-b---F--- M| -| R6|F-F-F---F---F---F-F-F--- T| R6|C-C-C---C---C---C-C-C--- A| R5|A-A-A---A---A---A-A-A--- B| N| L3|F-f----- A| L3|C-C----- B| L2|----b--- B| L2|----F--- E| L1|----b--- R| .| R6|F-F-F---F---F---F-F-F--- C| R6|C-C-C---C---C---C-C-C--- O| R5|A-A-A---A---A---A-A-A--- M| -| L3|F-F-F--- T| L3|--C----- A| L2|b---F--- B| N| R6|F-F-F---F---F---F-F-F--- A| R6|C-C-C---C---C---C-C-C--- B| R5|A-A-A---A---A---A-A-A--- B| E| L3|F-f----- R| L3|C-C----- .| L2|----b--- C| L2|----F--- O| L1|----b---

C,f,a,f,a,g,,f,d,c,c,f,a,f,a,g,c,a,,c,a,f,c,d,a,a,c,f,a,f,a,g,f

F, B, f, f, f, f#, f c#, B, B, c, c, c#, B, c, c#, B, B, B, F#, F, F#, F, A, c, A, B.

C F F D C F C Bb A A Bb C F G A. C F F D C F

78°C converts to 172.4°F

C, F, F, F C, G, E, F C, F, B, B, A, G, F, E, F, G C, F, F, F, C, G, E, F, C, F, A, C, A, F, D, G, A, F

C f f f c ^g e f c f ^a^c^a f g c e f

A variable is a symbol that stands for a value that may vary. It only changes if you edit a value of something else For example, in the formula "=CONVERT(A2,"C","F")" (Convert cell "A2" from degrees Celsius to Fahrenheit), "C" and "F" are variables with specific meanings. As second variable could also be "C" or "F", it's value varies.

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