Factor out each number into primes to get: 38 = 2 * 19 20 = 2² * 5 28 = 2² * 7 Count the maximum number of distinct primes for all of these values. For instance, if 20 and 28 both have the maximum number of "2" 2, then write out 2². If one number has a prime factor while the rest of the number doesn't, then write out that prime factor. Following these steps, we have this product: 2² * 5 * 19 * 7 = 4 * 5 * 7 * 19 = 2660 So that is the LCM of the given numbers.
No since it is an even number it has 2 as a factor. If the factors are the number itself and 1 it is prime. If there are more factors it is not. 28 has many more factors.28=22 x7So 2 and 4 and 7 are all factors as is 14.
Their only prime factor is 4.
I think you misworded your question. I am not exactly sure what you are looking for. If you want to know the prime factorization of the number 28, it is, 2^2 * 7. That is two squared times seven.
7,2,2 14,2 28
Because 7 is a factor of 28 and 63 and 7 is a prime number.
No, 1 is not a prime number.
1, 4, 14, 28
It is: 7
2 and 7
Yes it's a factor of 28 for example and it's a prime number
28 is a factor of 28, as 28/28 = 1. 28 is also a multiple of 28, as 28*1 = 28.
The least common prime factor of 24 and 28 is 2.
Prime factor each number. Circle all the prime common factors then, multiply them 28=2x2x7 32=2x2x2x2x2 GCF=2x2=4
The highest common factor of both number is 28
28 has two prime factors: 2 and 7.
28 (22*7)