2,0
We can draw 3 normals to a parabola from a given point as the equation of normal in parametric form is a cubic equation.
A point lies on a line if the coordinates of the point satisfy the equation of the line.
Without an equality sign it can not be considered to be an equation
If ... the square of (the x-coordinate of the point minus the x-coordinate of the center of the circle) added to the square of (the y-coordinate of the point minus the y-coordinate of the center of the circle) is equal to the square of the circle's radius, then the point is on the circle.
The given expression is not an equation because it has no equality sign
True
We can draw 3 normals to a parabola from a given point as the equation of normal in parametric form is a cubic equation.
A point lies on a line if the coordinates of the point satisfy the equation of the line.
A. The hexagon is circumscribed about the circle . D. Each vertex of the hexagon lies outside the circle . E. The circle is tangent to each side of the hexagon .
Without an equality sign it can not be considered to be an equation
If ... the square of (the x-coordinate of the point minus the x-coordinate of the center of the circle) added to the square of (the y-coordinate of the point minus the y-coordinate of the center of the circle) is equal to the square of the circle's radius, then the point is on the circle.
The given expression is not an equation because it has no equality sign
(6,2)
A number of point lies on it...................(-2,-44), (-1,-19),(0,6), (1,31), (2, 56)...............
Without an equality sign the given expression can't be considered to be an equation.
The given expression is not an equation because it has no equality sign
Center is at (Xc, Yc ). Radius = R. ======================================= Print "Input the coordinates of point 'P', separated by a comma." Input A, B D = (Xc - A)2 + (Yc - B)2 If D < R2 then print "'P' is inside the circle." If D = R2 then print "'P' is on the circle." If D > R2 then print "'P' is outside the circle." by arup nandy