Mass, possibly.
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph. Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
First, note that velocity is a vector quantity. This means it has a magnitude (the speed) as well as a direction. The magnitude of the velocity is the difference in position divided by difference in time. Hopefully, the direction should be evident from the graph.
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph.Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
take the slope of every change in the velocity time graph and plot it
It represent the distance covered is 40 metre.
the gradient of the graph
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph. Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
the physical quantity is distance and unit is meters
It cannot, in any sensible way.
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
First, note that velocity is a vector quantity. This means it has a magnitude (the speed) as well as a direction. The magnitude of the velocity is the difference in position divided by difference in time. Hopefully, the direction should be evident from the graph.
well, the area under the curve between a time interval is equal to the distance traveled on that specific time interval. So one quantity is distance. As for another quantity, the answer would be velocity, but I think they may want a less obvious answer. A quantity out side of velocity could be instantaneous acceleration. This is given by the slope of the the tangent line to the velocity-time graph.Hope this helps you answer your question. Though I think the most simple way to understanding why is to take a course of calculus.
That the object whose velocity is being graphed has reversed direction (and is now going in the opposite direction). Velocity is a vector quantity: it has both magnitude and direction.
A velocity time graph is still a velocity time graph - no matter the degree of detail that you look at it.
The radial velocity ie velocity towards or away from your starting point. It is NOT the ordinary speed or velocity because you can run in a circle around your starting point at top speed but the distance will not change so the slope of the distance time graph will be zero.
The average acceleration can be obtained by finding the slope of the graph. The instantaneous acceleration is found by drawing a tangent to a particular point on the graph (instant) and finding the slope of than tangent.
If an x-t graph is a position-time graph, velocity is the slope of the line on the graph.